5.56
moles of what?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
Mole Ratio
It depends a bit on what information you are given. However, the principle is the same in all cases, although how you do the specific calculation may vary a bit.As an example, let's say we have a mixture of 5.00 grams of water and 10.0 grams of ethanol (C2H5OH). What is the mole fraction of the two components?The first thing we must do is convert the number of grams of each substance into moles. To do that, see the Related Question below:How do you convert from grams to moles and also from moles to grams?For water, we have:5.00 grams ÷ 18.015 grams/mole = 0.2775 moles H2OFor ethanol, we have:10.0 grams ÷ 46.068 grams/mole = 0.2171 moles C2H5OHNow we can find the mole ratio, which is defined as follows:Moles ratio of compound X = number of moles of X ÷ total number of moles in mixtureSo the mole ratio of water is: 0.2775 ÷ (0.2775 + 0.2171) = 0.561 or 56.1%and the mole ratio of ethanol is: 0.2171 ÷ ((0.2775 + 0.2171) = 0.439 or 43.9%Check your answer! The total mole ratio for all components MUST add up to 1.00:0.561 + 0.439 = 1.00 Yes!Note that the weight ratio was 1-to-2 (twice as much ethanol as water by weight), but the mole ratio was completely different.
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
This ratio is 1:2.
moles of what?
The mass in grams of 3,20 moles of copper is 158,865 g.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
Mole Ratio
Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).
CuSO4 is water soluble. CaCO3 is not.
The ratio H/O is 2.
The answer is 159,62 g for the anhydrous salt.
0.25 Pb(NO3)2 + CuSO4 --> PbSO4 + Cu(NO3)2 stoichiometry is 1:1 for Pb(NO3)2 : CuSO4
M = moles solute/ Liters solution 1 mL= 0.001 L 0.990M x 0.001 L =9.9 x 10^-4 moles CuSO4 9.9 x 10^-4 *2 = 0.00198 solute particles *When you dissolve 1 mole CuSO4 in water, it dissolves into 1 mol of Cu+ ions and 1mol of SO4- ions, which gives you twice as many moles of solute particles- which is why you multiply 9.9 x 10^-4 by 2. Hope this helps