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In order to get the number of moles of a substance when given the mass of the substance you must divide the mass in grams by the molar mass of the substance, which for aluminum is 26.98. So the answer is 27/26.98 = 1.0007, which would be rounded to 1.0 mol.

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13y ago
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11y ago

The answer is in the question itself, although the end of the question should read "aluminum-29". When the name of an isotope is written in this manner, the number after the hyphen is the mass number of the isotope.

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14y ago

m=29 g M(Al)= 27 g.mol-1 nAl=m/M=29/27=1.074 moles N= number of atoms NA= Avogadro's number= 6 x 1023 n=N/NA N=n x NA = 1.074 X 6 X 1023= 6.4 X 1023 atoms.

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11y ago

27 g of Al has 6.023 x 1023 atoms.So, 23 g of Al will have 5.131 x 1023atoms.

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10y ago

9÷24=0.33333mol 0.33333 x 6.022 x 10^22 Number of atoms=2.0073x10^22

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Q: How many moles of aluminum atoms are present in 27g of aluminum?
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