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How many moles of calcium hydroxide are needed to react with 5.88 mL of nitric acid?
Wiki User
∙ 9y ago
The answer is 0,07 moles Ca(OH)2.
Wiki User
∙ 8y ago
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How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
How many moles of no2 will be obtained starting with 0.4 moles of nitric acid?
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
How many moles of calcium hydroxide are needed to neutralize 2 moles of sulfuric acid?
2HCl + Ca(OH)2 --> CaCl2 + 2H2O That means you need twice as many moles of HCl as you have of the Ca(OH)2 I'll let you do the math.
How many liters of 0.2 M calcium hydroxide do you need in order to have 6.0 moles of calcium hydroxide?
By definition, 0.2 N calcium hydroxide contain 0.2 moles per liter of the solution. Therefore, in order to have 6.0 moles total, one must have 6.0/0.2 or 30 liters. If the value given for molarity actually has only one significant digit as written in the question, this answer should be written as "3 X 10" to show that only one significant digit is justified by the input data.
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
How many moles of oxygen atoms are in 2.53 g of calcium hydroxide?
The answer is 0,068 mol (for O not for O2).
How many moles of no2 will be obtained starting with 0.4 moles of nitric acid?
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
How many moles of calcium hydroxide are needed to neutralize 2 moles of sulfuric acid?
2HCl + Ca(OH)2 --> CaCl2 + 2H2O That means you need twice as many moles of HCl as you have of the Ca(OH)2 I'll let you do the math.
How many liters of 0.2 M calcium hydroxide do you need in order to have 6.0 moles of calcium hydroxide?
By definition, 0.2 N calcium hydroxide contain 0.2 moles per liter of the solution. Therefore, in order to have 6.0 moles total, one must have 6.0/0.2 or 30 liters. If the value given for molarity actually has only one significant digit as written in the question, this answer should be written as "3 X 10" to show that only one significant digit is justified by the input data.
How many moles of ironIII hydroxide are needed to react with excess nitric acid to produce 63.8 g ironIII nitrate?
Balanced equation. Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O 63.8 grams Fe(NO3)3 (1 mole Fe(NO3)3/241.88 grams)(1 mole Fe(OH)3/1 mole Fe(NO3)3 = 0.264 moles iron III hydroxide needed ==========================
What is the mass of of 2 moles of Ca(CH)2?
If you trhink to calcium hydroxide - Ca(OH)2 - this mass is 148,086 g.
How many moles of base are needed to neutralize 2 mol of acid for HNO3 plus KOH?
Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
How many moles of NO are formed from 0.30 moles of O2?
Also 0,3 moles nitric oxide.
How many grams of calcium hydroxide can be produced from 312 g of CaO?
CaO has a gram molecular mass of 40.08 + 16.00 = 56.08. The reaction between CaO and water to produce calcium hydroxide, Ca(OH)2, occurs according to the equation CaO + H2O = Ca(OH)2. Therefore, the same number of moles of calcium hydroxide can be produced as the moles of CaO supplied. The gram molecular mass of Ca(OH)2 is 40.08 + 2 (16.00 + 1.008) = 74.10. Therefore, the mass of calcium hydroxide produced with have the same ratio to the mass of calcium oxide supplied as 74.10 has to 56.08, or 412 grams, to the justified number of significant digits.
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
