Since both the acid and the base have equivalent weights equal to their formula weights, 2 moles of KOH are needed to neutralize 2 moles of nitric acid.
Here's a small list of common acids. Just because it my be H2 doesnt make it a acid though. Hope this helps a little bit! Hydrochloric Acid=HCl Hydrobromic Acid=HBr Hydriodic Acid=HI Hydrofluoric Acid=HF Nitric Acid=HNO3 Sulfuric Acid=H2SO4 Perchloric Acid=HClO4 Acetic Acid=HC2H3O­2
nine. one amino acid is composed of three bases.
The pH of milk of magnesia is greater than 7 (it is around 9 or so). This makes it a weak base and therefore useful in treating stomach acid problems as it tends to neutralize the area.
Dipeptide,amino acid,polypeptide,protein Amino Acid is the answer
It is h20 and citric acid
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
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20 moles of NaOH needed to neutralize 20 moles of nitric acid
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
4 moles HNO3 (63.018 grams/1 mole HNO3) = 252 grams nitric acid ================
The number of moles of acid and the base should be equal to neutralize. (So the number of moles of base is needed to answer this correctly)
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH. 1.32 grams HNO3 (1 mole HNO3/63.018 grams) = 0.020946 moles nitric acid ------------------------------------- Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters ) Molarity = 0.020946 moles HNO3/0.750 Liters = 0.027928 M HNO3 ----------------------------------finally, - log(0.027928 M HNO3) = 1.55 pH ==========( could call it 1.6 pH )
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
Make sure that the equation is balanced. NaOH + HNO3 > > NaNO3 + H2O ( all one to one ) 15.0 grams NaOH (1mol NaOH=39.998g) (1mol HNO3/1mol NaOH) = 0.375 moles of HNO3 Molarity = mols solute/volume solution 2.00M HNO3 = 0.375 mols/X volume = 0.188 Liters or, 188 milliliters.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
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