The subscript in the chemical formula C2H6 tells you that one C2H6 molecule contains 2 carbon atoms. Or, in terms of moles, 1 mol C2H6 contains 2 mol C. This mole ratio can be used as a conversion factor.
500 mol C2H6 x 2 mol C = 1000 mol C
........................1 mol C2H6
The formula C2H6 shows that there are two carbon atoms in each molecule of the compound. Since the formula mass for elemental carbon is a single atom, 500 moles of the compound will contain 1000 moles of carbon.
The Law of Definite Proportions states that for every mole of ethane, there will be two moles of carbon. Then there is 1 mole of carbon in one half a mole of ethane.
There is one mole of carbon per one mole of CCl4. So if there is 0.5 mole of CCl4 then there are 0.5 moles of C in CCl4.
0.5 x 6.022x1023 =3.011x1023 CO2 molecules =3.011x1023 Carbon Atoms
The answer is 1 mol carbon.
1.00 mole
1.00
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
350 g C2H6 x 1 mole C2H6/30 g x 2 moles C/mole C2H6 x 12 g/mole C = 280 g carbonDone another way: %C = 24/30 (x100%) = 80% 0.8 x 350 g = 280 grams carbon
77.28 grams C2H6 (1 mole C2H6/30.068 grams)(2 mole C/1 mole C2H6)(6.022 X 10^23/1 mole C) = 3.096 X 10^24 atoms of carbon
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
The Law of Definite Proportions states that for every mole of ethane, there will be two moles of carbon. Then there is 1 mole of carbon in one half a mole of ethane.
7/2O2+C2H6->2CO2+3H2O Mole ratio of C2H6:CO2=1:2 No.of mole of CO2=2mol
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
350 g C2H6 x 1 mole C2H6/30 g x 2 moles C/mole C2H6 x 12 g/mole C = 280 g carbonDone another way: %C = 24/30 (x100%) = 80% 0.8 x 350 g = 280 grams carbon
77.28 grams C2H6 (1 mole C2H6/30.068 grams)(2 mole C/1 mole C2H6)(6.022 X 10^23/1 mole C) = 3.096 X 10^24 atoms of carbon
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
In each mole of ethanol there are two moles of carbon atoms. One mole of carbon atoms is required to form one mole of carbon dioxide, so two moles will form two moles. Thus each mole of ethanol completely combusted will form two moles of carbon dioxide.
The same. 0.233 moles C (1mol C/1mo CO2 ) = 0.233 moles of Carbon.
30.0 grams carbon (1 mole C/12.01 grams) = 2.50 moles carbon ===============