The formula for Ethylene_ C2H4 STEP 1 Calculate the RMM (Relative molecular mass) of C2H4 C-carbon= 12; H-hydrogen= 1 (check your Periodic Table people!!!) C*2 + H*4 = 12*2 + 1*4 = 24 + 2 =28 amu/g So... one mole of ethylene has a mass of 28 grams. Number of Moles= Mass / mass of 1 mole ("/" to divide) The mass given is 122g 122g/28g = 4.36 moles Approx 4.4 moles
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
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Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
How many moles of atoms are contained in 382 g Co
74.3 g Na2CrO4 x 1 mole/162 g = 0.459 moles (3 sig figs)
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
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63 g of water are needed.
Moles = mass in grams / atomic weight So moles in 15.01 g of Ar = 15.01 / 39.948 = 0.38 moles
0,27 moles of calcium contain 10,82 g calcium.
35.0 moles nitrogen (1 mole N/14.01 grams) = 2.50 moles nitrogen ----------------------------
# moles = mass / molar mass = 1.23g / 83.80g/mol =1.47x10^-2 moles There are 1.47x10^-2 moles in 1.23g of krypton
0 moles
Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.
16 grams of oxygen how many moles is 0,5 moles.
How many moles of atoms are contained in 382 g Co