0
How many moles of fecr2o7 are required to produce 107. moles of fe2o3?
Wiki User
∙ 6y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
How many moles of Fe2O3 are in 231 g of the compound?
231 g of Fe2O3 are equal to 0,69 moles.
How many mole of KI required to produce 0.4 moles K2HgI4?
the required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4 moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore 1.6 moles of KI is required to produce 0.4 moles of K2HgI4
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many moles of Fe are present in 30 grams in rust?
This amount may be different because rust is not a clearly definite compound.
What is the molarity when 160.0 grams of Fe2O3 is dissolved to make 1.0 liters of solution?
Molarity = moles of solute/Liters of solution Get moles of Fe2O3 160.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams) = 1.0 mole Molarity = 1.0 mole/1.0 liters = 1.0 M Fe2O3
What mole ratio would you use to determine moles Fe if moles Fe2O3 is known?
X moles Fe2O3 (2 moles Fe/1 mole Fe2O3) 2 : 1
How many Fe atoms are in 0.25 moles of Fe?
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
How many moles of Fe2O3 are in 231 g of the compound?
231 g of Fe2O3 are equal to 0,69 moles.
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
How many atoms in iron oxide Fe2O3?
There are 6 atoms of oxygen represented by this.
How many moles of Fe3O4 are needed to prepare 4.74 moles of Fe2O3?
7.18
What mass of hydrogen chloride is require to react with 100 g of rust?
Taking rust to be Fe2O3, you would have the following reaction:Fe2O3 + 6HCl ==> 2FeCl3 + 3H2O100 g Fe2O3 x 1 mole Fe2O3/159.7 g = 0.626 moles Fe2O3moles HCl needed = 0.626 moles Fe2O3 x 6 moles HCl/mole Fe2O3 = 3.76 moles HCl neededMass HCl needed = 3.76 moles HCl x 36.5 g/mole = 137 g HCl needed
How many moles of fe2o3 are in 217g of the compound?
1.358
What are some parts of a chemical change?
Depict moles eg: Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g) 1 mole of Fe2O3 4 moles of CO 2 moles of Fe 3 moles of CO2
How many mole of KI required to produce 0.4 moles K2HgI4?
the required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4 moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore 1.6 moles of KI is required to produce 0.4 moles of K2HgI4
If 4.00 kg of Fe2O3 are available to react how many moles of CO are needed and how many moles of each product are formed?
mass / molar mass molar mass Fe2O3 = 159.69 g/mol mass Fe2)3 = 4.00 kg = 4000 g moles = 4000 g / 159.69 g/mol = 25.05 moles Fe2O3 The balanced equation tells you that 1 mole Fe2O3 requires 3 moles CO to react So 25.05 moles needs (3 x 25.05) moles CO = 75.15 moles Co is needed to react 4.00 kg Fe2O3 = 75.2 mol (3 sig figs) b) The equation tells you that 1 moles Fe2O3 reacts to form 2 moles Fe So 25.05 moles will form (2 x 25.05) mol Fe moles Fe formed = 50.10 moles = 50.1 mol (3 sig figs) The equation tells you 1 mole Fe2O3 reacts to form 3 moles CO2 So 25.05 mol Fe2O3 will form (3 x 25.05) mol CO2 = 75.15 moles CO2 = 75.2 mol (3 sig figs) ==
