How many moles of gas are in a volume of 66.3 at STP?
I am going to assume that you mean 66.3L.
1 mole gas = 22.4L
66.3L gas x 1mol/22.4L = 2.96 moles gas
At RTP the assumed temperature is 293ºK, at STP the assumed temperature is 273ºK. The formula used for this is Pressure x Volume = moles x ideal gas constant x Temperature. So Volume = (moles x ideal gas constant x temperature) / Pressure Assuming Pressure and moles stays constant... Volume at RTP = ( 1 mole x 8.31451 x 293 K ) / ( 101.325 Pa) Volume at RTP = 24.0429 Volume at RTP =…
Because you're in STP conditions, you can use molar volume in a proportion. Molar volume is the volume one mole of an ideal gas will take up at STP: 22.4 liters/mole. To set up a proportion, think: if one mole of a gas occupies 22.4 liters, then 4.0 moles of a gas will occupy x liters. 1 mole/22.4 L = 4.0 mole/X L x = 44.8 liters