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22.4L
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What does avogadros law say about a gas at STP?
1 mole of gas at STP occupies 22.4 liters.
What is the volume of a mole of any gas at standard temperature and pressure?
The volume of a mole of any gas at Standard Temperature and Pressure (STP) is approximately 22.4 liters. This is known as the molar volume of a gas at STP and is a standard value used in gas calculations.
One mole of N2 gas at STP will occupy what volume?
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
What is the volume of one mole of any gas at STP?
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
What volume will the Cl2 occupy at STP?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
According to avogadros law what is characteristic of 1 mole of gas at STP?
It occupies 22.4 L
What volume does 22g of CO2 at STP occupy?
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
What does a molar volume of a gas at STP occupy?
At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. This is known as the molar volume of a gas at STP.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
What is the volume of 1.42 mol of ammonia at STP?
At standard temperature and pressure (STP), the volume occupied by 1 mole of any ideal gas is 22.4 liters. Therefore, the volume of 1.42 moles of ammonia at STP would be 1.42 * 22.4 liters = 31.808 liters.
At STP 32 grams of O2 would occupy the same volume as?
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L
What is the volume of 0.8 moles of chlorine gas at Standard Temperature and Pressure?
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
