5 moles H2O (1 mole O/1 mole H2O)(6.022 X 1023/1 mole O)(1 mole O atoms/6.022 X 1023)
= 5 moles oxygen atoms
=================( as you see this is a formal set up that you do not need to use fully as Avogadro's number is over itself as a form of one )
5 moles H2O (2 moles H/1 mole H2O)6.022 X 1023/1 mole H)(1 mole H atoms/6.022 X 1023)
= 10 moles hydrogen atoms
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4 moles of oxygen atoms are present in 4 moles of H2O
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
Diphosphorus pentoxide has 5 oxygen atoms per molecule according to the given prefix. So, 5 moles of it will be 5 x 5 x (6.022x10^23) = 1.51x10^25 oxygen atoms.
One molecule has four H atoms.So two moles have 8 moles
4 moles of oxygen atoms are present in 4 moles of H2O
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
Glucose is C6H12O6 and thus the mole ratio is 6 moles of carbon to 6 moles of Hydrogen Molecules (12 moles of Hydrogen atoms) and 3 moles of oxygen molecules (6 moles of oxygen atoms)
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
There is 25.0 moles Oxygen
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
3KNO3, so 9 oxygen atoms.
Diphosphorus pentoxide has 5 oxygen atoms per molecule according to the given prefix. So, 5 moles of it will be 5 x 5 x (6.022x10^23) = 1.51x10^25 oxygen atoms.
One molecule has four H atoms.So two moles have 8 moles
20 x 2 x 6.022x1023 = 2.409x1025 atoms of oxygen
Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.