2 moles of Ca and 4 moles of OH
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
That would be 2 moles of OH- (hydroxide) ions because there are 2 of them associated with each 1 of the group II metal.
Two moles is equivalent to 12,044281714.10e23 molecules, atoms or ions.
20.4
B4O7^2- + 7H2O = 4H3BO3 + 2OH- B4O7^2- : 2OH- = 1:2 Therefore there are twice the number of moles of Hydroxide ions produced as there are Borate ions
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
2
Na2CO32 * 2 = 4 moles sodium.===========================
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
There are 9 moles of NH4 (Ammonium ions) in Ammonium carbonate. There are 2 moles of NH4 per molecule and 4.5 molecules, so 2 moles times 4.5 is 9 moles.
Balanced equation first.Mg + Cl2 -> MgCl2All is one to one, so,0.25 moles of chlorine ions are needed here.================================
2
2.4088 x 1024 chloride ions
1.20442 x 1024 chloride ions
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
That would be 2 moles of OH- (hydroxide) ions because there are 2 of them associated with each 1 of the group II metal.
2.4088 x 1024 nitrate ions