74 g magnesium (1 mole Mg/24.31 g)(6.022 X 1023/1 mole Mg)(1 mole Mg atoms/6.022 X 1023)
= 3.0 moles of magnesium atoms
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As you see Avogadro's number is over itself as a form of one, so only the moles of Mg need be found. This depiction is the formal set up.
water = 18.0 g / mole
7.5 g of water = 2.508*10^23
In 7.6 mole MgS there is 7.6 mole Mg(2+) AND 7.6 mole S(2-)
About tree fiddy
0.0214 mol
There are 0.13 moles in 20 grams of magnesium nitrate.
0.2 mol
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
0.0214 mol
1,11 moles of magnesium have 26,97855 g.
There are 0.13 moles in 20 grams of magnesium nitrate.
1
88,1 moles of magnesium is equivalent to 2 141,27 g.
the formula is no. moles is mass / molecular mass. As the number of moles is 1, the mass required will be exactly the same as the molecular mass, which is 58.32g
0.2 mol
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
A lot
13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
0,15 moles NaOH contain 6 g.