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2KClO3 + heat -> 2KCl + 3O2

14 moles KClO3 (3 mole O2/2 mole KClO3)

= 21 moles oxygen made

This is a common industrial method of producing oxygen.

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Q: How many moles of oxygen are produced from 14 moles of potassium chlorate?
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Related questions

How many moles of potassium chlorate are needed to give 1.50 moles of oxygen?

The answer is 1 mole potassium chlorate.


How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?

2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3


How many moles of oxygen are produced from twelve moles of potassium chlorate?

12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.


How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?

Four moles of potassium chlorate are needed.


How many moles of oxygen are produced when 7.5 moles of potassium chlorate decompose completely?

2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.


How many moles of potassium chlorate produce 6 moles of oxygen gas?

The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.


How many moles potassium chlorate must be used to produce 6 moles of oxygen gas?

We need 3 moles of potassium perchlorate.


How many moles of potassium chlorate are needed to produce 15 moles of oxygen?

Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.


How many moles of potassium chlorate (KClo3) must be used to produce 6 moles of oxygen?

2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.


Why would lithium chlorate be a more practical choice for the chlorate candle?

because it depends on the number of the moles that you will get, so the more moles number that you have for the chlorate the more oxygen that you will get.


How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?

You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed


Hoy many moles of potassium nitrate are produced when 2 moles of potassium phosphate react wth 2 moles of aluminum nitrate?

there are two moles produced in potassium nitrate.