2KClO3 + heat -> 2KCl + 3O2
14 moles KClO3 (3 mole O2/2 mole KClO3)
= 21 moles oxygen made
This is a common industrial method of producing oxygen.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
because it depends on the number of the moles that you will get, so the more moles number that you have for the chlorate the more oxygen that you will get.
there are two moles produced in potassium nitrate.
2 to 3, because of the balanced equation:2 KClO3 --> 2 KCl + 3 O2
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
The answer is 1 mole potassium chlorate.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
Four moles of potassium chlorate are needed.
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
We need 3 moles of potassium perchlorate.
Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
because it depends on the number of the moles that you will get, so the more moles number that you have for the chlorate the more oxygen that you will get.
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
there are two moles produced in potassium nitrate.