Since oxygen is diatomic it requires 2 moles of oxygen.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
3,7 moles of C8H11NO2 have 3,7 moles of oxygen (O2).
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
65
800 g oxygen are needed.
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
999 g
16 grams of oxygen how many moles is 0,5 moles.
3,7 moles of C8H11NO2 have 3,7 moles of oxygen (O2).
10 moles of oxygen atoms or 5 moles of oxygen molecules.
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
The nunber of moles of oxygen is 2,5.