A. A balance chemical equation of burning of ethene is
C2H4 + 3O2 ____ 2CO2 + 2H2O
now according to balance chemical equation
1 mole of ethene burn by using 3 moles of oxygen so to burn
10 moles of ethene 3 x 10 30 moles of oxygen will be required.
This is a reaction that I do not remember the name of, but, no matter, balanced equation first.
2Mg + O2 >> 2MgO
10 moles Mg (1mol O2/2mol Mg)
= 5 moles oxygen gas needed.
5 moles of oxygen (O2) are needed.
Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
The answer is 0,274 moles.
how many moles of sulfur are present in 3.4 moles of Al2(SO4)3
10 g of carbon is equivalent to 0,8326 moles.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
10
Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.
4NH3 + 3O2 -----> 2N2 + 6H2O 4 moles of ammonia react with 3 of oxygen. So 10 moles of ammonia requires 7.5 moles of oxygen.
The answer is 10 moles.
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
The answer is 7,18.10e-10 moles.
Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )
The answer is 0,274 moles.
Molarity = moles of solute/volume of solution. 1 liter = 1000 millilitetrs 3.00M = X Moles/1000ml = 3000 millimoles, or 3 moles NaCl 3 moles NaCl (58.44g NaCl/1mol NaCl ) = 175.32 grams needed. About 4/10 of a pound of salt.