The answer is 10 moles.
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
1,93
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
4,2.10e25 H atoms
200g times 342.2965 g/mol = 68459.3 moles
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
2
18.24
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
2.95 mole H2O (2 moles H/1 mole H2O) = 5.90 moles hydrogen ------------------------------
The number of atoms is 52,63.10e23.
2.08 moles H2O (2 moles H/1 mole H2O)(1.008 grams H/1 mole H) = 4.19 grams of hydrogen ===================
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
One molecule has four H atoms.So two moles have 8 moles
1,93
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms