You can make a simple balance.
There are
(12.36 * 3) moles of H
You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
The answer is 699 moles perchloric acid.
These reagents doesn't react.
Four moles of potassium chlorate are needed.
800 g oxygen are needed.
The answer is 3,424 mol sucrose.
The answer is 699 moles perchloric acid.
319g Cl2 are needed.
This is based on calculations too. It contains 18 hydrogen moles.
These reagents doesn't react.
Four moles of potassium chlorate are needed.
800 g oxygen are needed.
Assuming a decomposition reaction with this equation: 2KClO3(s) --> 2KCl(s) + 3O2(g), the ratio is 2:3, and if you produce 15mol O2, then 10mol potassium chlorate are needed.
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
The volume is 254,82 L.
The answer is 3,424 mol sucrose.
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The needed mass of sodium is 91,659 g (for 2 moles H2).