0
hahaha ur soo dum u dont know lol go to dumbppl.com dumbo
Wiki User
∙ 12y ago
kai .
Add your answer:
Earn +20 pts
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of H2 are needed to produce 12.36 of NH3?
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
How many moles of NH3 are produced when 1.2 moles of H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
This is based on calculations too. It contains 18 hydrogen moles.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
How many moles of hydrogen are needed to make 170000 g of ammonia?
170 kg = 170,000g NH3 = 170,000g / 17.0g/molNH3 = [10,000 molNH3] * 3moleH2 / 2moleNH3= 15,000 mole H2 needed to produce 170 kg NH3
How many moles of H2 are needed to produce 12.36 of NH3?
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of NH3 are produced when 1.2 moles of H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of H2O can be formed when 4.5 moles of NH3 react with 3.2 moles of O2 NH3 plus O2 yields NO plus H2O?
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
How many moles of NH3 are produced when 1.2 moles H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
