To determine the molar mass of propane (C3H8), add the atomic masses of all the atoms present:
3C = 3x12 = 36
8H = 8x1 = 8
Total = 36 + 8 = 44 g/mole = molar mass of propane
Simple conversion, take the 88 moles of propane and divide by the molar mass of propane.
88g divided by 44.11g/moles = 1.995 moles, which rounds to 2.0 moles.
(8.88 x 1023 molecules) X (1 mol / 6.022 x 1023 molecules) = 1.47mol
moles = weight / molecular weight = 88 / 44 = 2
1 mole of propane weight 44 g. So two moles will weigh 88 g.
9 is used
0.25 mol
44.5
50
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
1 moles CF4 = 88.0043128 grams. CF4 = 171 grams / 88 grams = 1.9431 moles
Propane has a density of .0018794 g/cm3. in 22.4 liters, there are 22400 cm3, so there are 42.10 grams of propane. The molar mass of propane is 44.10 g/mole, so there are .955 moles. Via Avogadro's number, there are then 5.751 E23 molecules of propane present.
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
3,80 g Zn have 0,058 moles.
5.8
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
1 moles CF4 = 88.0043128 grams. CF4 = 171 grams / 88 grams = 1.9431 moles
Propane has a density of .0018794 g/cm3. in 22.4 liters, there are 22400 cm3, so there are 42.10 grams of propane. The molar mass of propane is 44.10 g/mole, so there are .955 moles. Via Avogadro's number, there are then 5.751 E23 molecules of propane present.
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
3,80 g Zn have 0,058 moles.
The formula is: number of moles = g Be/9,012.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The answer is 0,253 moles.
The answer is 0,4 moles.
The answer is 0,364 moles.
573,28 of g of AgCI is equivalent to 4 moles.