Quite a few.
6.32 X 10^25 atoms sodium (1 mole Na/6.022 X 10^23)
= 105 moles of sodium
4.06 X 1025 molecules NaF (1 mole NaF/6.022 X 1023) = 67.4 moles sodium fluoride =====================
5.0x10^25 * (1 mol / 6.022x10^23 atoms) = 83 moles of iron.
1.30*1025
A mole of potassium consists of Avogadro's number of atoms. Therefore 6.85 X 1025 atoms comprises (6.85 X 1025)/(6.022 X 1023) or 114 moles, to the justified number of significant digits.
7.30 C2H6O (6 moles H/1 mole C2H6O)(6.022 X 1023/1 mole H) = 2.64 X 1025 atoms of hydrogen =====================
In order to find how many Moles of He are 1.20 x 1025 atoms of He, you need to divide 1.20 x 1025 atoms by the Avagadro's number (6.022 x 1023) The answer is 19.9 moles of He.
4.06 X 1025 molecules NaF (1 mole NaF/6.022 X 1023) = 67.4 moles sodium fluoride =====================
20.4 MOLES OF PCl3
5.0x10^25 * (1 mol / 6.022x10^23 atoms) = 83 moles of iron.
1.30*1025
A mole of potassium consists of Avogadro's number of atoms. Therefore 6.85 X 1025 atoms comprises (6.85 X 1025)/(6.022 X 1023) or 114 moles, to the justified number of significant digits.
100 times Avogadro's Number = 6.022 X 1025.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
8.30 moles (NH4)2S (8 moles H/1 mole (NH4)2S)(6.022 X 1023/1 mole H) = 3.99 X 1025 atoms of hydrogen ========================
7.30 C2H6O (6 moles H/1 mole C2H6O)(6.022 X 1023/1 mole H) = 2.64 X 1025 atoms of hydrogen =====================
The element magnesium does not form polyatomic molecules with specific numbers of atoms. Therefore, one mole ofmagnesium contains Avogadro's Number of atoms, and Avogadro's number is about 6.022 X 1023. Therefore, 1.48 X 1025 atoms contains (1.48/6.022) X10(25-23) or about 24.7 moles, to the justified number of significant digits.
The element helium does not technically have "moles", because its atomsdo not form any chemical bond with other helium atoms. Its formula unit is a single atom. Avogadro's Number, the number of formula units in a gram atomic mass, is about 6.022 X 1023. Therefore, 1.20 x 1025 atoms constitutes (1.20 X 1025)/(6.022 X 1023) or about 19.9 formula masses, to the justified number of significant digits.