250 M means contains 250 moles per liter, which is probably impossible 1) . However, taking the question as stated, the answer is (2.0 mole)/(250 moles/liter) = 0.0080 liter or 8.0 milliliters, to the justified number of significant digits.
1) Commented: It is impossible!
The solution in this question is really impossible in every way:
The density if pure KCl is (less than) 1.984 g/cm3 , being equal to 0.027 mol/mL =
27 mol/L with NO solvent added. ( = 27 M)
%(v/v) = [(volume of solute)/(volume of solution)] x 100% 2% =[(volume of solute)/250 mL] x 100% 2%/100% = volume of solute/250 mL 0.02 x 250 mL = volume of solute 5 mL = volume of solute
Molarity (M) = mols / L
0.4 = mol / 0.250L
mol = (0.4) (0.250)
mol = 0.1
The answer is 0,625 moles.
1 mole in 250 ml and 4 moles in 1 liter or 1000 mls
By using the formula V1 x N1 = V2 x N2 Taking V1= 250 ml; N1= 0.35M; N2= 5.7M. V2 = volume of 5.7M needed to dilute V2 = V1 x N1 N2 = 250 x 0.35 = 15.35ml 5.7
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
the total solution volume will be 100ml since were adding 25ml of ethanol then the volume of water used in will be 100-25=75ml the percentage by volume of the solution is 25/100 X 100/1 = 25%
.01 M
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
25 mL
The answer is 48,17 L.
For a 10 % solution you need 250 g KCl.
The water volume is 212,5 mL.
1cc (cubic centimeter) and 1mL (milliliter) are the same volume. So, 250mL is the same as 250cc
The solution has a total mass of 30 + 250 = 380 g. The mass percent of calcium chloride in this solution is 100(30/380) = 7.9 %, to the justified number of significant digits.
1 mole in 250 ml and 4 moles in 1 liter or 1000 mls
10 mL
By using the formula V1 x N1 = V2 x N2 Taking V1= 250 ml; N1= 0.35M; N2= 5.7M. V2 = volume of 5.7M needed to dilute V2 = V1 x N1 N2 = 250 x 0.35 = 15.35ml 5.7
There are many ways to measure concentration, but the most useful is Molarity, the number of moles of the solute divided by the volume (in Liters) of the solvent. For instance, a 1M salt solution contains 1 mole of salt in 1L of water.
25% ammonia solution means 25g Ammonia in 100ml of water. To convert it into moles i.e for 1000ml solvent, 25x100=250 which means 250g of ammonia is present in 1000ml of water to make a 25%solution. To convert it into molar solution we will divide 250 by the molecular mass of ammonia i.e 17. 250/17= 14.71M This means that 25% ammonia solution contains 14.71 moles of ammonia. Now we will use the formula M1V1=M2V2 Let's say we want to make 10 molar solution in 500ml water. Then, M1=14.71 V1=? M2=10 V2=500 Putting values in the above equation: 14.71xV1 = 10x500 V1 = 10x500 / 14.71 = 340ml We will take 340ml of the 25% ammonia solution and make the volume up to 500ml with water. This will be our 10 molar solution of Ammonia.