3 pairs
It can only make three bonds. Boron has three valence electrons and therefore cannot form more than three bonds with no lone pairs.
4 pairs
Boron has 3 valence electrons, which allows it to covalently bond to three other atoms. Each of the 3 covalent bonds has a pair of valence electrons, which means boron is sharing a total of six valence electrons in a compound. Boron still prefers an octet. Therefore, Boron can share a fourth bond which means boron will share 8 valence electrons, a full octet. But in this case, boron will have a formal charge: 3 valence - 4 bonds = -1 charge. The structure with 4 covalent bonds is similar to carbon (think CH4), but because boron has one less proton than carbon, boron carries a negative formal charge when boron fills its octet by covalently bondingto 4 atoms.An example of this would be the acid-base reaction:BF3 + diethyl ether (C2H5)2OThe oxygen will use one of its lone pair of electrons to form a covalent bond with boron.This means boron has a minus one formal charge and has 3 bonds (with 3 fluorines)and one bond to oxygen. The oxygen now is sharing one of its lone pairs in a covalentbond, so the oxygen has a plus one formal charge now: 6-3-2=+1.
B is in the center, with the three F's around it. Two F's have three lone pairs of electrons and one F has two lone pairs and a double bond with B.
ow many valence electrons in methyl fluoride/
boron has 2 pairs
It can only make three bonds. Boron has three valence electrons and therefore cannot form more than three bonds with no lone pairs.
Borondoesn't follow the octet rule in that many of its compounds are electron deficient. The B has 3 valence electronsand each F has 7 valence electrons, so 3*7=21+3 is 24 valence electrons in total. As the Lewis diagram will reveal, the B is connected to 3 atomsand has no lone pairs, thus sp2.
4 pairs
In the element bromine (Br), there is only 1 unpaired electron. It has 7 valence electrons, so 3 pairs, plus an unpaired electron.
Boron has 3 valence electrons, which allows it to covalently bond to three other atoms. Each of the 3 covalent bonds has a pair of valence electrons, which means boron is sharing a total of six valence electrons in a compound. Boron still prefers an octet. Therefore, Boron can share a fourth bond which means boron will share 8 valence electrons, a full octet. But in this case, boron will have a formal charge: 3 valence - 4 bonds = -1 charge. The structure with 4 covalent bonds is similar to carbon (think CH4), but because boron has one less proton than carbon, boron carries a negative formal charge when boron fills its octet by covalently bondingto 4 atoms.An example of this would be the acid-base reaction:BF3 + diethyl ether (C2H5)2OThe oxygen will use one of its lone pair of electrons to form a covalent bond with boron.This means boron has a minus one formal charge and has 3 bonds (with 3 fluorines)and one bond to oxygen. The oxygen now is sharing one of its lone pairs in a covalentbond, so the oxygen has a plus one formal charge now: 6-3-2=+1.
B is in the center, with the three F's around it. Two F's have three lone pairs of electrons and one F has two lone pairs and a double bond with B.
The answer is not 6 as said here before! The number of valence electrons in O2 (oxygen molecule) is: 12 valence electrons. 6 of them from each oxygen (O) atom. 4 valence electrons make up the double bond between the two oxygen atoms, and the remaining 8 valence electrons form lone pairs (non-bonding pairs) on the oxygen atoms, 2 lone pairs on each. I hope there is some help in this.
If an atom has five valence electrons, it will have one lone pair of electrons.
lone pairs
ow many valence electrons in methyl fluoride/
These pairs of electrons are referred to as lone pairs.