From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23.
is this correct this is not the answer just a further question ...
Mass = (mol)*(mol mass) = 1.140 (mol) * 65.38 (g/mol Zn) = 74.53 g Zn
0,1377 x 65,4 = 9 grams of zinc
65.3800 g/mol
One mole of zinc is 65.38 grams.
65.39g
135 grams zinc (1 mole Zn/65.41 grams)(6.022 X 10^23/1mole Zn) = 1.24 X 10^24 atoms of zinc
amu = 1.66 X 10^-27 kg Find mass of 2500 atoms Zn in kg. 2500 atoms Zn (1mole Zn/6.022 X 10^23)(65.41 grams/1 mole Zn)(1 kg/1000 g) = 2.72 X 10^-22 kilograms/1.66 X 10^-27 = 1.64 X 10^5 amu
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
12 grams zinc (1 mole Zn/65.41 grams)(6.022 X 1023/1 mole Zn) = 1.1 X 1023 atoms zinc ==================
Zn + S ==> ZnSmoles Zn = 25 g x 1 mol/65.4 g = 0.38 moles Znmoles S = 300 g x 1 mol/32 g = 9.38 moles Smoles S in excess = 9.38 - 0.38 = 9.00 molesmass S in excess = 9 moles x 32g/mol = 288 g = 280 g (to 2 significant figures)
3.29 moles Zn x 6.02x10^23 atoms/mole = answer (do the math)
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3 moles of Zn is equal to 18.09x1023 atoms. I used Avogadro's Number : 6.03x1023 particles/mol This number is the number of atoms or molecules in a mol of any substance. 3 moles X 6.03x1023 particles/mol = 18.09x1023 atoms
Molar mass of Zinc = 65.4 g mol-1 No. of moles of 20.0 g of Zinc = 20.0 / 65.4 = 0.305810397 mol No. of atoms = 0.305810397 L (where L is the Avogadro constant) = 1.8416 x 1023
3.65(g) / 65.38(g/mol) = 0.0558 (mol)
There are : 1 zinc atom 2 chlorine atoms 6 oxygen atoms in this zinc chlorate molecule.
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
I assume zinc limits in this reaction. Balanced equation. Zn + 2HCl -> ZnCl2 + H2 184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn) = 2.81 moles zinc chloride produced ==========================
Also 5,8 mol
For Apex the answer is 2
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn