The formula you are looking for is W = A x V.
To calculate the amperage, you can use the formula A = W / V, where A is amperage, W is watts, and V is voltage. Thus, for 4800 watts at 220 volts, the amperage would be 21.82 amps.
The power (in watts) can be calculated using the formula: Power (W) = Voltage (V) * Current (A). In this case, the power required to run the 3 amp well pump on 220 volts is 660 watts (220 V * 3 A = 660 W).
Yes! One HP equals 749 watts. W = V . I 220 . 7 = 2.056 In reality, with 7 amps in 220 v you have more than 2 HP. By Nonô - BRAZIL Yes! One HP equals 749 watts. If you have 7 amps on 220 v, as watt = volts . amps, 220 . 7 = 1540 watts 1540 / 7498 = 2.056 HP. You have more than 2 hp. By Nonô - BRAZIL
This depends on the voltage ... amps = watts / volts 660 W / 110 V = 6 amps 660 W / 220 V = 3 amps 660 W / 330 KV = 2 mA
Watts from a socket is dependant upon what the load connected draws. The maximum capacity from a socket is calculated by the following equation, W = A x V. So the maximum wattage you are able to draw from the socket before the fuse blows is W = 13 x 220 = 2860.
To calculate the current in amps for a 2 kV system with a primary voltage of 380 V and a secondary voltage of 220 V, you need to know the transformer's power rating (in watts) or the load connected. The formula to determine the current is ( I = \frac{P}{V} ), where ( P ) is the power in watts and ( V ) is the voltage in volts. For a 2 kV (2000 W) system, at 220 V, the current would be approximately ( I = \frac{2000 W}{220 V} \approx 9.09 ) amps. If you are looking for the primary current, you would use the primary voltage of 380 V instead.
P=VI here P=8000 Watts v=220 V I=8000/220 = 37 A so you should use 37A Breaker
Five amps is 600 watts on 120 v and 1200 watts on 240 v.
P = I x V P = 22 x 220 Therefore Power consumed = 4840 Watts Or 4.84kW
The higher voltage need more resistance, from the formula W = V2 / R. That means R = V2 / W. So 220 v 100 W is 484 ohms, while 115 v 100 W is 132¼ ohms.
To determine the size of the breaker needed for a 9,000-watt broiler operating at 220 volts, you can use the formula: Amperage (A) = Watts (W) / Volts (V). In this case, 9,000 W / 220 V = approximately 40.91 A. It's common practice to add a safety margin, so a 50-amp breaker would be appropriate to handle the load safely.
As watts are made of volts times amps, the answer would be 0.660kw.