For 1 meter cube of brick work, you would need approximately 13 bags of cement.
M 15 grade - 1:2:4Cement bags required - 6.5 bagsCement required - 325 kgs
For M20 grade concrete, the mix proportion is 1:1.5:3 (cement:sand:coarse aggregates). If we consider a volume of 1 cubic meter, approximately 320 kg of cement would be needed.
The ratio of sand and cement affects the tensile strength of the concrete. Hence, a ratio of 1:2 (cement to sand) will yield a greater tensile strength than a 1:3 ratio. However, both are acceptable in the formation of concrete.
1 USD per ton oh ulo moh!!
315 Kg/M3 approx.
it depends on the type of mix and water cement ratio.
How much crsand for 1 m3 concrete
As ratio is 1 : 2 : 4, there are 1 + 2 + 4 = 7 parts in totalTherefore 1 part is 1 m3 ÷ 7 = 1/7 m3cement : sand : gravel = 1 : 2 : 4→ 1 x 1/7 m3 : 2 x 1/7 m3 : 4 x 1/7 m3 =1/7 m3 ≈ 0.14 m3 cement;2/7 m3 ≈ 0.29 m3 sand;4/7 m3 ≈ 0.57 m3 gravel[mortar and concrete is mixed by volume.]
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As much as the engineered load calls for to perform the task the cement is required to perform.
75 m3 of natural gas.
quantity of cement for M20 in one cubic metercement=1440 kg/m3sand=1700 kg/m3aggregate= 1600 kg/m3Lets solve for M20 i.e, 1:1.5:31 bag of cement = 50 kg =34.7 litres=35 litresi.e, 0.035 m3(item) (w/c ratio)(water) (cement)(sand)(aggregate)volume(0.42)(21ltr)(0.035)(0.0525)(0.105)voids - (0) (0) (0 60%) (40%) (45%)solidvolume (-) (0.021) (0.014) (0.0315) (0.05775) *sum=0.124Thus 50 kg of cement gives 0.124 m3 of concrete for M20 at 0.42 w/c ratio.Hence,cement required =0.035/0.124 =0.28 m3 i.e, 0.28*1440=403kgsand required= 0.0525/0.124 =0.42 m3 i.e, 0.42*1700 = 714 kgsimilarly aggregate required = 1360 kgwater required = 169 litreCheck: 403+714+1360 = 2477 i.e, density of concrete =2477kg/m3*NOTE: The quantity of cement, sand, aggregate & water varies with the w/c ratio and the density of materials.
i dn k=12*45
for preparing cement mortar C.M.(1:6) number of cement bags required are nearly 5.14 bags.calculation: for preparing 1 cu.m wet C.M(1:6), dry material required is 25% extra.therefore dry material required is 1.25 cu.mhence cement required=1.25/(1+6)=0.178 cu.m(sand required=0.178*6=1.068 cu.m)density of cement=1440 kg/cu.m=>cement required in kg=0.178*1440=256.32cu.mwt. of cement in kg per bag=50kgtherefore no. of bags required is=26.32/50=5.14bags.thank u.
For 1 meter cube of brick work, you would need approximately 13 bags of cement.
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