The equation you are looking for is I = W/E. Amps = Watts/Volts.
The answer is 1500 divided by 120 and it's in amps.
It is 1500 divided by 120.
Load!
The maximum current that can be drawn from a voltage source is dependent on the impedance of that source, the impedance of the connections to the source, and the energy available from that source.
p=r*i
maximum demand is measured in kva because current drawn is dependent on power factor for the same load and current drawn is calculated with kva
at lower power factor current drawn by load is high and at higher pf the current drawn is less...
If they are in series, the total resistance is 150 ohms so the current is 120/150 amps. If they are in parallel, the current is 120/100 plus 120/50 amps.
Load!
load
It is a the current drawn by the application that is connected to the power source
A 6000 watt toaster oven, if one could exist, would pull 50 amperes from a 120 volt supply.The question is unrealistic, because the maximum branch current for a normal circut would be about 16 amperes, using the 80% rule, and that would produce about 2000 watts.
No tangent No tangent
The maximum current that can be drawn from a voltage source is dependent on the impedance of that source, the impedance of the connections to the source, and the energy available from that source.
nothing..............
None
The mgnetic inrush current is the current drawn by the transformer when power is applied to the primary winding
The rated current is the maximum current that can be drawn in normal continuous use, without any reduction in the lifetime of the device.
If the terminal voltage decreases when more current is drawn, that is due to the internal resistance of the power supply. Every power supply has a limit to how much current can be drawn. It is limited by the internal resistance and due to ohms law the more current drawn through a resistor, then the more voltage is produced across it. This is in opposition to the terminal voltage and is subtracted from it.