Want this question answered?
-- The voltage makes no difference. -- The 400W device dissipates ten times as much power as the 40W device does. We don't know how much of each one's power consumption is radiated in the form of heat, UV light, etc. But if the spectral distribution of their output is similar, then the one that dissipates more power produces more visible light, and appears brighter.
It means that the power consumption of the bulb is 40 watts.
The first thing you have to do is find out how much you are being charged per kWh from the utility company. 40 watts is .040 kW. If the bulb was left on for an hour.040 kWh times what you are charged from the utility company and you will have your answer. Now that you have read a simple answer, lets add reality. A 40W T-8/T-10/T-12 fluorescent bulb requires a specialized fixture for it to function. As part of that fixture a starter and ballast are included that also must be powered at nominal 80% efficiency and add cost to the user. The next factor that must be considered has to do with environmental costs. each method of illumination does so via creation of heat. The heat must be dissipated and offset. The nominal temperature at the exciter of a 40W fluorescent tube is 110 degrees F with 70 degree F ambient environment. The nominal temperature of a fast start ballast (starter included) is 130 degrees F in the same ambient environment. This stated, the cost to run a single 40W fluorescent tube one hour will be the sum of the 40W consumed by the bulb plus the cost to run the fixture plus the cost to offset the additional heat produced. Therefore expect to use your cost per KWh times .048 plus environmental cost. Remember that even in incandescent lighting the environmental factors also play.
75W means bulb which give 75W power when connected to domestic light. Power is nothing but energy per second. Thus energy consumed by bulb can be calculated as follows. E = 75*60*60*4J = 1080kJ
The average home fluorescent lamp consumes 40W of power. Running for one hour it will consume 0.04 KWh. Units of electricity are charged per Kilowatt hour.
It's the 40W tube! because it's nonlinear: indeed it generates harmonics which increase the apparent power and thus the apparent energy.
-- The voltage makes no difference. -- The 400W device dissipates ten times as much power as the 40W device does. We don't know how much of each one's power consumption is radiated in the form of heat, UV light, etc. But if the spectral distribution of their output is similar, then the one that dissipates more power produces more visible light, and appears brighter.
It means that the power consumption of the bulb is 40 watts.
Voltage x Current = Power So Power / voltage = current Now you do the math
were is the place were 12 06s and 78 40w
easy as 1 2 3
You probably worded your question wrong, since the answer would be 40w. But I'll work out the charge to run it for you. I am working your questions using the MELBOURNE, AUSTRALIA power tariff (charge) which is 17.000c per kw/h. It takes roughly 25 hours for your 40w fluoro tube to consume 1 kilowatt of power, so the power consumption per hour would be around 0.0068 cents an hour. Please take note of other amounts of electricity that have to be used in order to fire up your tube though, as some starter capacitors can use a big amount of energy (this is the reason why it is not recommended to use fluoro bulbs on 12v/24v - 240v/110v inverters). So basically, if you are going to be out of the room for less than 1 hour, leave it on.
40 watts is the same as 0.04 kW, so you can multiply that by the number of hours to get the energy.
Treating this as an ideal resistance, voltage will be half, so current will be half. Power (which is V * I) is one fourth, so you will only draw 10W.
greenland
No...TIP31 is NPN. The complementary PNP is a TIP32. They are both large high power (40W) devices.