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How much energy is needed to raise the temperature of 2.0 grams of water of 5.0 Celsius?
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∙ 6y ago
42 J
Taya Kuphal
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How do you calculate the total heat required in kcal to take 70 grams of ice at -29.0 Celsius and convert it to steam at 106 Celsius?
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
How much energy is required to raise 21kg of water by 2 degrees Celsius?
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
Is 50 grams 96 degrees Celsius 148 meters or 259 liters a measurement of volume?
Liters measure volume. Grams are a measure of mass, degrees Celsius are a measure of temperature, and meters are a measure of length.
How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?
21 grams through 71 degrees is 21x71 calories.
H20 a mass of 48.0 grams a temperature of -58 celsius how many joules of energy necessary to heat the steam 100.0 celsius to 114.0 celsius specific heat of the steam is 2.01 j g c?
Formula: q = m x C x ΔTq = amount of heat energy gained or lost by substance = ?m = mass of sample in grams = 48.0gC = heat capacity (J/g•oC) = 2.01 J/g•oCTf = final temperature = 114.0oCTi = initial temperature = 100.0oCΔT = (Tf - Ti) = 14.0oCSolution:q = 48.0g x 2.01 J/g•oC x 14.0oC = 1350 J
How much energy is needed to increase the temperature of 755 grams of ironfrom 283Kelvin to 403Kelvin?
quite abit
How much energy is needed to reduce water temperature from 15 degrees to 14 degrees?
1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
The temperature would be that of water's boilng point od 100 degrees
How do you increase the the temperature of 500 grams of water from 20 degrees Celsius to 100 degrees Celsius?
q(joules) = mass * specific heat * change in temperature q = (500 grams H2O)(4.180 J/goC)(100o C - 20o C) = 1.7 X 105 joules ================add this much heat energy to the water
How do you calculate the total heat required in kcal to take 70 grams of ice at -29.0 Celsius and convert it to steam at 106 Celsius?
heat energy required to raise the temperature of ice by 29 celsius =specific heat capacity of ice * temperature change *mass of ice + to change 1kg of ice at 0 celsius to water at 0 celsius =specific latent of fusion of ice*mass of water + heat energy required to raise the temperature of water by 106 celsius =specific heat capacity of water * temperature change *mass of ice + to change 1kg of water at 106 celsius to steam at 106 celsius =specific latent of fusion of ice*mass of steam
How many grams of camphor are needed to raise the boiling point of 43.5 grams of benzene by 2.10 Celsius?
5.2
How much energy is required to raise 21kg of water by 2 degrees Celsius?
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
How many kilojoules of energy are necessary to raise the temperature of 3 kilograms of cast iron from 30 degrees celsius to 120 degrees celsius?
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
How much heat in joules is needed to raise the temperature of 4.0 L of water from 0 degrees Celsius to 70.0 degrees Celsius?
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
How much energy would you need to raise the temperature of 50G of copper by 30 degrees Celsius?
To find the energy needed to raise the temperature of a substance, we can use the equation Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. For copper, the specific heat capacity is approximately 0.386 J/g°C. Converting the mass from grams to kilograms (50 g = 0.05 kg), we can plug in the values to calculate the energy: Q = (0.05 kg) * (0.386 J/g°C) * (30°C) = 0.579 J Therefore, you would need approximately 0.579 joules of energy to raise the temperature of 50 grams of copper by 30 degrees Celsius.
How much heat energy will be required to lower the temperature of 2.67kg of steam from 282 degrees Celsius to 105 degrees Celsius?
You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.
