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How much octane can react with 0.740 of oxygen?
1 mol of octane (C8H18) reacts with 25 mol of oxygen (O2) to produce 8 mol of CO2 and 9 mol of H2O. Therefore, 0.74 mol of oxygen can react with 0.0744 mol of octane.
How much hydrogen would be required to produce 7.5 mol of water?
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
How much nitrogen is in nitrogen di oxide?
1 mol of nitrogen per 1 mol of oxygen. NO2
How much energy does sugar supply?
-5.63mJ/mol
How much energy is in 1 mol of an x-ray photon with a wavelength of .180 nm?
6.65X10^5 kj/mol
1 mol off sulfur atoms has how much mass?
The molar mass of sulfur is approximately 32.06 grams/mol. Therefore, 1 mol of sulfur atoms will have a mass of 32.06 grams.
What does mol mean in light bulbs?
MOL refers to MAXIMUM OVERALL LENGTH. MOL is Maximum Overall Length measurement. MOL of bulb is measured from top of bulb to bottom of Bulb base (or bottom of pins.) Exception is if bulb has flexible wire leads, then measurement does NOT include the length of wires. Actual bulb is likely shorter (sometimes much, much shorter) than the MOL industry standard specification.
How much ice is consumed by thawing 4.3 g ice?
4.3 g * 1 mol/18.02 g * 6.03 kJ/mol
How much energy is generate from freezing 2.5 g water?
2.5 g 1 mol/18.02 g (-285.83) kJ/mol
How much mass does 1 mol of o2 gas have?
15.99 x 2 g
How much does 2.18 mol of Cu weigh?
The molar mass of copper (Cu) is approximately 63.55 g/mol. To calculate the weight of 2.18 mol of copper, you would multiply the number of moles by the molar mass: 2.18 mol x 63.55 g/mol ≈ 138.49 g. Therefore, 2.18 mol of copper weighs approximately 138.49 grams.
When 10.0 mol of calcium metal is reacted with 3.4 mol of oxygen gas how much calcium oxide is produced?
To determine how much calcium oxide is produced, we first need to consider the balanced chemical reaction: 2 Ca + O₂ → 2 CaO. From the reaction, 2 moles of calcium react with 1 mole of oxygen to produce 2 moles of calcium oxide. Given 10.0 mol of calcium and 3.4 mol of oxygen, calcium is in excess since it requires only 1.7 mol of oxygen (10.0 mol Ca / 2 = 5 mol CaO produced). Therefore, 3.4 mol of oxygen can fully react with 6.8 mol of calcium, yielding 6.8 mol of calcium oxide produced.
