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How much liquid oxygen is needed to produce two liters of gaseous oxygen?
Vevans
At standard temperature and pressure, one mole of gas takes up 22.4 liters. So the amount of gas necessary to occupy 2 liters is:
2 L ÷ 22.4 mole/L = 0.08929 moles
One mole of oxygen gas (O2) weighs 32 grams per mole, so:
0.08929 moles * 32 g/mole = 2.857 grams of O2
The density of liquid oxygen is 1.141 g/cm³, and so the volume is:
2.857 grams ÷ 1.141 g/cm3 = 2.50 cm3 = 2.50 mL
In other words, oxygen expands by a factor of 800 going from liquid to gas!
See the Related Questions link to the left for more information on solving Ideal Gas Law problems of this type.
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∙ 16y ago
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