The answer is 0,86 meq.
164
The equation is: NaCl----------Na++ Cl-
The cation, or positively charged ion, in NaCl is Na+.
NaCl---------------→Na+ + Cl-
Na+ + Cl- --> NaCl NaCl = salt.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
Na+ + Cl- --> NaCl NaCl = salt.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
Pure solide NaCl is not electrically conductive. The water solution of NaCl is an electrolyte and is conductive.
(22.99 g/mol Na / 58.43 g/mol NaCl ) x 100 ppm NaCl= 39.35 ppm Na
(7.6 g NaCl) (moles NaCl/58.44 g NaCl) (1 mole Na/1 mole NaCl) ( 22.99 g Na/mole Na) = 2.989 g Na or 3.0 g Na (significant figures) Steps: 1. Change everything to moles: use molar mass/molecular of NaCl 2. Find the molar ratio: since there are 1 Na in every NaCl, then the ratio of NaCl to Na is 1:1 3. Change moles back to grams: use the molar mass/molecular weight of Na 4. Watch out for significant figures! I hope this is right