[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 Mass of Na in 7,6 grams of NaCl = 0,39337 x 7,6 g = 2,99 g
Amount of NaCl = 8.0/58.5 = 0.137mol In each unit of NaCl there is one Na+ ion. Mass of Na = 0.137 x 23.0 = 3.15g
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 200 mL of 0,45 % sodium chloride contain 0,9 g NaCl. Mass of Na in 0,9 grams of NaCl = 0,39337 x 0,9 g = 0,354 g
Sodium has an atomic weight of 23 and chlorine has an atomic weight of 35.5 and there is one atom of each in each molecule of NaCl, so one molecule of NaCl has a total atomic weight of 58.5. The fraction of that weight that is chlorine is then 35.5/58.5 or about 0.607. Therefore, from the decomposition of 85.0 g of NaCl you would get 85.0 X 0.607 = about 51.6 grams. You can fill in more precise numbers if you would like and recalculate, but that would be my answer.
.22352 grams
(7.6 g NaCl) (moles NaCl/58.44 g NaCl) (1 mole Na/1 mole NaCl) ( 22.99 g Na/mole Na) = 2.989 g Na or 3.0 g Na (significant figures) Steps: 1. Change everything to moles: use molar mass/molecular of NaCl 2. Find the molar ratio: since there are 1 Na in every NaCl, then the ratio of NaCl to Na is 1:1 3. Change moles back to grams: use the molar mass/molecular weight of Na 4. Watch out for significant figures! I hope this is right
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 Mass of Na in 4,1 grams of NaCl = 0,39337 x 4,1 g = 1, 613 g
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 Mass of Na in 7,6 grams of NaCl = 0,39337 x 7,6 g = 2,99 g
I'm going to assume that you mean 23.34g of NaCl. 1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams) 23.34g NaCl x (1mol NaCl/58.442g NaCl) = 0.3994mol NaCl
The molecular weight of sodium (Na) is 22.99 grams. The molecular weight of chlorine (Cl) is 35.45 grams. Therefore, there are 58.44 grams in 1 mole of NaCl. So, in 3.25 moles of NaCl, there are 58.44 gr x 3.25 = 189.93 grams.
1 teaspoon of salt (NaCL) = 6 grams of NaCL or 2,360 mg of sodium (Na). (Na molecular wt is 23, Cl is 35.5, so NaCl is 58.5, so Na is 40 % times grams of wt of NaCl.) So 1 gram NaCl X 1 tsp/6 g NaCl = 0.16667 tsp NaCl or if you want Sodium ( how salt is expressed on food labels) then 1 gram of Na X 1 tsp NaCl/2.360 gram Na = 0.42 tsp Na.
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
Amount of NaCl = 8.0/58.5 = 0.137mol In each unit of NaCl there is one Na+ ion. Mass of Na = 0.137 x 23.0 = 3.15g
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 200 mL of 0,45 % sodium chloride contain 0,9 g NaCl. Mass of Na in 0,9 grams of NaCl = 0,39337 x 0,9 g = 0,354 g
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
Example: sodium chloride, NaCl Atomic weight of chlorine: 35,45 Atomic weight of sodium: 22,989 769 28 Molar mass of NaCl=sum of the atomic weights of Cl and Na: 58,439 769 28 Expressed in grams, also 58,439 769 28 g.