NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g
Na has an atomic weight of 22,989 769 28 g.
% Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337
200 mL of 0,45 % sodium chloride contain 0,9 g NaCl.
Mass of Na in 0,9 grams of NaCl = 0,39337 x 0,9 g = 0,354 g
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
The mass of sodium hypochlorite in 2,5 kg solution is 131,25 g.Sodium chloride is only the product of a decomposition.
The percentage of sodium in NaCl is 39,666.So, 75 x 39,666/100= 29,75 g sodium in 75 g NaCl
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
The answer is 1,98 g sodium.
1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================
The answer is 8 g NaCl.
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
The mass of sodium hypochlorite in 2,5 kg solution is 131,25 g.Sodium chloride is only the product of a decomposition.
The answer is 28,81 %.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
The percentage of sodium in NaCl is 39,666.So, 75 x 39,666/100= 29,75 g sodium in 75 g NaCl
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
0.9% w/v (weight per volume, otherwise known as grams per 100ml) sodium chloride is NaCl abbreviated