250 g sodium chloride contain 99,16 g sodium.
The answer is 25 g; dissolve 25 g NaCl in 1 L demineralized water, at 20 0C, in a volumetric flask.
0.9% means there is 0.9 grams NaCl per 100ml of solution. So 1000 ml of 0.9% sodium chloride contains 9.0 grams of NaCl.
Normal saline is 0.9% weight/volume sodium chloride to water. This is 9 grams per litre. NaCl has a molecular weight of 58.5, sodium (Na) has a weight of 23, which is 39.3% of the molecular weight. So sodium is 39.3% of the weight. 1 litre of saline has 9 grams, 250ml is a quarter of a litre, so has 9/4 grams = 2.25 grams. 39.3% of 2.25 g is 0.884 grams of sodium.
Two moles of sodium chloride is equivalent to 116,88 (rounded) g.The molar mass of NaCl 58.5 grams per mole. 117 grams of salt is equivalent to two moles. Dissolve this much of salt in exactly 1L of distilled water in a volumetric flask to prepare 2M NaCl.
The formula unit of sodium chloride (NaCl) contain 60,33 % chlorine.
117 grams of NaCl
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
2 grams of salt = 2,000 mg of sodium
Sodium chloride has two atoms in the formula unit.
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
The answer to the question is 120 grams of water :)
58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-
The answer is 11,5 mg NaCl for 1 L water.