Multiply the force by the distance. The mass is irrelevant for this problem.
Work = (force) x (distance)Without motion, there is no work, no matter how great the force.
First you need to calculate the work required. This is simply force x distance in this case.Once you have that, divide the work by the time.
get a force meter The most common tests done on safety shoes are: - impact resistance - compression resistance - penetration resistance For impact resistance a weight is dropped on the the toe-cap. Then it's measured how much millimeter the toe cap was indented. For compression resistance a gradual force is applied on the toe cap until it breaks or a certain number of millimeters of indent is reached For penetration resistance a nail is pushed through the sole and the protective mid plate, again the indent and force applied is measured.
Newton's third law of motion can be used. This law of motion states that any force has an equal and opposite force. This can be proven by simply pushing away from a table. When you push you are putting a certain amount of force on the table. This force is pushed back (opposite) with the same amount of force (equal) pushing you away. In turn, you can say that when you push away from a table you are using as much force as it would take you to move yourself. The Bernoulli's principle would also apply. It states that a force applied to a fluid is transmitted equally throughout the fluid in all directions. (This only slightly applies to this question.)
If there is no force against motion,applied force is zero. If there is force against motion,applied force is equal and opposite to that force.
400 J
400 J
Multiply the force by the distance. The mass is irrelevant for this problem.
Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.
If a force of 20 N acts through a distance of 15 m, then it does (20 x 15) = 300 joules of work.The other facts of the case, such as the mass of the crate being pushed, don't matter.
If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.
Work = force x distance = Newtons x meters = 1937 Joules.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
compression is the force pushed on and object. The formula for how much pressure during compression is: force/area.
If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.
That depends also on the direction of force, though it simplifies greatly if force is all the way applied exclusively in the direction of movement. Work doesn't depend on the mass too. Formula is(assuming the direction of applied force is the same as of displacement): W = F * r, where W - work, F - force, r - displacement. For given data, it will be: W = 20 * 15 = 300 J