400 J
Multiply the force by the distance. The mass is irrelevant for this problem.
Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.
If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.
Work = force x distance = Newtons x meters = 1937 Joules.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
400 J
Multiply the force by the distance. The mass is irrelevant for this problem.
Multiply the force by the distance. The mass is irrelevant for this problem.
Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.
If a force of 20 N acts through a distance of 15 m, then it does (20 x 15) = 300 joules of work.The other facts of the case, such as the mass of the crate being pushed, don't matter.
If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.
Work = force x distance = Newtons x meters = 1937 Joules.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
We must assume that the force pushes parallel to the floor.Work = (force) x (distance) = (800) x (1.5) = 1,200 newton-meters = 1,200 joules
compression is the force pushed on and object. The formula for how much pressure during compression is: force/area.
If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.
That depends also on the direction of force, though it simplifies greatly if force is all the way applied exclusively in the direction of movement. Work doesn't depend on the mass too. Formula is(assuming the direction of applied force is the same as of displacement): W = F * r, where W - work, F - force, r - displacement. For given data, it will be: W = 20 * 15 = 300 J