0
c = lambda * nunu = c/lambda = 3x10^8 m/sec /9x10^-8 m = 0.33 sec^-1
E = h*nu
E = 6.626x10^-34 Jsec * 0.33sec^-1
E = 2.2x10^-34 Joules
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThe energy is 13,776 eV.
Add your answer:
Earn +20 pts
What is the energy of a 500 nm photon?
The energy of a 500 nm photon is 3.1 eV (electron volts). This is a unit of measure used to represent the energy of a single photon. To put this into perspective, a single photon of visible light has an energy of 1.8 to 3.1 eV, and a single photon of ultraviolet light has an energy of 3.1 to 124 eV. The energy of a 500 nm photon can be calculated by using the following equation: E = hc/ Where: E = energy of the photon (in eV) h = Planck's constant (6.626 * 10-34 Js) c = speed of light (2.998 * 108 m/s) = wavelength of photon (in meters) Therefore, the energy of a 500 nm photon is calculated as follows: Convert the wavelength from nanometers to meters: 500 nm = 0.0005 m Insert the values into the equation: E = (6.626 * 10-34 Js) * (2.998 * 108 m/s) / (0.0005 m) Calculate the energy: E = 3.1 eVTherefore, the energy of a 500 nm photon is 3.1 eV.
What is the relationship between wave length and energy on the electromagnetic spectrum?
The relationship between electromagnetic energy (photon energy) and wavelength is determined by two constants - the speed of light and Planck's constant. Photon energy (in Joules) is equal to the speed of light (in metres per second) multiplied by Plancks constant (in Joule-seconds) divided by the wavelength (in metres). E = hc/wavelength where: E is photon energy h is Planck's constant = 6.626 x 10-34 Js c is the speed of light = 2.998 x 108 m/s This relationship shows that short wavelengths (e.g. X-rays) have high photon energies while long wavelengths (e.g. Radio waves) have low photon energies.
What equation is used to calculate the energy of a photon?
Planck's Equation,E = hvWhere E is the energy contained within the photon of light, h is Plank's constant, and v is the frequency of the light.Planck's constant, h, = 6.626068 X 10 ^ -34 J s and frequency of light = speed of light / wavelengththis is not only used in light but also to find energy of all electromagnetic radiation
What is the wavelength of a photon with a frequency of 6.901014 hz?
Wavelength = 3 x 108 / 6.9 *1014 lambda = 4.35*10-7 m Almost the colour seems to be violet.
What is the energy of a photon with a wavelength of 550 nm?
frequency is given as f=c/L, where c is the speed of light and L is the wavelength of the electromagnetic wave. Using c=3*108 m/s, we get 3*108/(550*10-9)=545*1012Hz=545 THz Remember that Hz=1/seconds such that units fit
What are the frequency and wavelength of the photon?
c = wavelength X frequency, where c is the speed of light, which is 299,792,458 m/s. So you need the wavelength of the photon. Then you divide c/wavelength and the result will be the frequency.
What is the energy of a 500 nm photon?
The energy of a 500 nm photon is 3.1 eV (electron volts). This is a unit of measure used to represent the energy of a single photon. To put this into perspective, a single photon of visible light has an energy of 1.8 to 3.1 eV, and a single photon of ultraviolet light has an energy of 3.1 to 124 eV. The energy of a 500 nm photon can be calculated by using the following equation: E = hc/ Where: E = energy of the photon (in eV) h = Planck's constant (6.626 * 10-34 Js) c = speed of light (2.998 * 108 m/s) = wavelength of photon (in meters) Therefore, the energy of a 500 nm photon is calculated as follows: Convert the wavelength from nanometers to meters: 500 nm = 0.0005 m Insert the values into the equation: E = (6.626 * 10-34 Js) * (2.998 * 108 m/s) / (0.0005 m) Calculate the energy: E = 3.1 eVTherefore, the energy of a 500 nm photon is 3.1 eV.
What is the wavelength of a photon with an energy of 3.26 10 19 J?
The wavelength is 610 nm.
What is the relationship between wave length and energy on the electromagnetic spectrum?
The relationship between electromagnetic energy (photon energy) and wavelength is determined by two constants - the speed of light and Planck's constant. Photon energy (in Joules) is equal to the speed of light (in metres per second) multiplied by Plancks constant (in Joule-seconds) divided by the wavelength (in metres). E = hc/wavelength where: E is photon energy h is Planck's constant = 6.626 x 10-34 Js c is the speed of light = 2.998 x 108 m/s This relationship shows that short wavelengths (e.g. X-rays) have high photon energies while long wavelengths (e.g. Radio waves) have low photon energies.
What equation is used to calculate the energy of a photon?
Planck's Equation,E = hvWhere E is the energy contained within the photon of light, h is Plank's constant, and v is the frequency of the light.Planck's constant, h, = 6.626068 X 10 ^ -34 J s and frequency of light = speed of light / wavelengththis is not only used in light but also to find energy of all electromagnetic radiation
What is the wavelength of a photon with a frequency of 6.901014 hz?
Wavelength = 3 x 108 / 6.9 *1014 lambda = 4.35*10-7 m Almost the colour seems to be violet.
A typical wavelength of infrared radiation emitted by your body is 25 micrometers. What is the energy per photon of such radiation?
* E = hf = hc/wavelength = (6.63 x 10-34 J*s)(3.00 x 108 m/s)/(25 x 10-6 m) = 7.9 x 10-21 J per photon. This is the energy of a photon at that wavelength. == The person who asked the question answered it. Why ask a question to which you already know the answer? And the body under "normal" conditions radiates infrared (IR) most strongly at about 10 micrometers.
A photon has a wavelength 624 nm. Calculate the energy of the photon in joules.?
You know that,E = h*c/λWhereh = Plank's constant = 6,626 x 10-34 J*sc = speed of light = 3*108 m/sλ = greek letter lambda representing the wavelength =624nm => 6,24 *10-7mand therefore [(6.626 X 10^-34 J) X (3 X 10^8 m/s)] / (6.24 x 10^-7) = 3.18 x 10^-19 ... That should be right!
How do you calculate wavelength to energy?
You can use Plank's relation to calculate the energy of the absorbed photon.E = h.f = h.c/LgivenE = Energy of a photon in Joulesf = frequency of the photon in s-1c = speed of light in m/sL = wavelength of the photon in metreh = Planck constant = 6.62606957×10−34 J.s
What is the energy in J of a photon with a wavelength of 495 nm?
E = hc/(wavelength) (Sorry but there ain't no button for lambda on the keyboard) h = 6.63 x 10-34, c = 3 x 108 E = (6.63 x 10-34 x 3 x 108) / 495 x 10-9 E = 4.0181818... x 10-19 NB if the wavelength is in nanometers, expect the final order of magnitude to be 10-19 or thereabout.
What is the energy of a photon with a wavelength of 550 nm?
frequency is given as f=c/L, where c is the speed of light and L is the wavelength of the electromagnetic wave. Using c=3*108 m/s, we get 3*108/(550*10-9)=545*1012Hz=545 THz Remember that Hz=1/seconds such that units fit
What happens as the frequency of photons increases?
For electromagnetic radiation,c = speed of light = 3.0 x 108 m/s = frequency x wavelengthAs the frequency of light waves increase, the wavelength decreases. For electromagnetic radiation, the wavelength times the frequency equals the speed of light, c, which is 3.0 x 108 m/s. So, if the frequency increases, the wavelength will decrease, and if the wavelength increases, the frequency decreases.
