Well in C++:
#include <iostream>
int main()
{
char x;
for(int i = 0; i < 255; i++)
{
x = i;
std::cout << i << "\t" << x << std::endl;
}
char wait;
std::cin >> wait;
return 0;
}
#include <stdio.h>
void main()
{
int c;
printf("Please enter a string, terminate with Ctrl+Z");
for ((c=getchar())!=EOF) printf ("%c %d\n", c, c);
}
You'd have to convert the value to the char type.
Example(C):
#include <stdio.h>
...
int n = 65;
printf("%c\n", n); //printf treats n as a character due to %c flag
....
Example(C++):
#include <iostream>
...
int n = 65;
std::cout << (char)n << std::endl; //here the conversion is needed
...
The following code demonstrates two ways to print characters and their ASCII equivalent. Note that although C++ treats all character as a numeric value, you must cast the numeric value to a numeric type (such as a short) in order to print the value, rather than the symbol associated with the value. Similarly, if you have a numeric value (such as a short) that represents a char, you must cast the numeric value to a char in order to print the symbol.
#include<iostream>
int main()
{
for(char c=65; c<91; ++c )
std::cout<<c<<" = "<<(short)c<<std::endl;
for(short s=97; s<123; ++s )
std::cout<<(char) s<<" = "<<s<<std::endl;
}
Basically what i need the code to do is to change a string of characters in to either uppercase or lowercase depending on wether or not the 3 input character is upper or lower case (i.e. if uppercase if will convert the string entirely into uppercase and if lower to lowercase)
so far i have this....
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main (void)
{
char array [65];
int i, c2;
fgets (array, 65, stdin);
c2 = array[2];
for (i = 0; array[i]; i++) {
. if (isupper (c2) && isupper (array[i])) {
. . array[i] = tolower (array[i]);
. } else if (islower (c2) && islower (array[i]) {
. . array[i] = toupper(array[ i ]);
. }
}
printf("Output is: %s\n", array);
}
In order to print a character using its ASCII value, you need to first assign it to a char value like this: char c = (char) 65; In this example, we are casting the int 65 to a char, which converts it to an 'A', since 65 is the ASCII value for the capital letter 'a'. Next, you can print it out if you want: System.out.println(c); That's pretty much all there is to it!
#include<stdio.h> #include<conio.h> void main() { int a=1; while(a<=255) { printf("%d=%c",a,a ); a++; } getch(); }
In C a character already is its ASCII value: char c= 'A'; printf ("%c is %d (0x%x hexa)\n", c, c, c);
Its Unicode value is 221A according to System tool Character map Advanced view Unicode subrange Math operators. But I haven't done C in awhile, so I don't know how to or if you can. ASCII value of root symbol is 251. In C we can print this symbol by printing the character value as below printf("%c",251); this will print the root symbol
Although character data types such as char are intrinsically numeric, whenever you print a char you automatically print the symbol associated with the character code (the char's value), never the code. In order to print the code you must cast the character to a numeric data type, such as int. char c = 'A'; // ASCII value 65 decimal (0x41) std::cout << static_cast<int>(c); // puts the value 65 on std::cout
In order to print a character using its ASCII value, you need to first assign it to a char value like this: char c = (char) 65; In this example, we are casting the int 65 to a char, which converts it to an 'A', since 65 is the ASCII value for the capital letter 'a'. Next, you can print it out if you want: System.out.println(c); That's pretty much all there is to it!
int main (void) { int i; for (i=32; i<=127; ++i) printf ("%3d: '%c'\n", i, i); }
I believe characters have a toUpper() function. For example: char x = 'a'; printf("%c\n", x.toUpper()); // This should print "A" You could also add or subtract using ascii values - remember, a char is pretty much an integer, just displayed differently. For example: printf("Character %c = decimal %d\n", x, x); will display your character and its ascii integer equivalent.
In C, an integer and a character are the same thing, just represented differently. For example: int x = 65; printf("x = (int) %d, (char) %c\n", x, x) should print "x = (int) 65, (char) A" You can also use the atoi (ascii to integer) and itoa (integer to ascii) functions.
The ASCII value for "C" is 67, for "c", 99.
#include<stdio.h> #include<conio.h> void main() { int a=1; while(a<=255) { printf("%d=%c",a,a ); a++; } getch(); }
In C a character already is its ASCII value: char c= 'A'; printf ("%c is %d (0x%x hexa)\n", c, c, c);
Its Unicode value is 221A according to System tool Character map Advanced view Unicode subrange Math operators. But I haven't done C in awhile, so I don't know how to or if you can. ASCII value of root symbol is 251. In C we can print this symbol by printing the character value as below printf("%c",251); this will print the root symbol
Although character data types such as char are intrinsically numeric, whenever you print a char you automatically print the symbol associated with the character code (the char's value), never the code. In order to print the code you must cast the character to a numeric data type, such as int. char c = 'A'; // ASCII value 65 decimal (0x41) std::cout << static_cast<int>(c); // puts the value 65 on std::cout
# include<stdio.h> main() { int a,b,c; print f("enter the values of a,b,c"); scan f("%d%d%d",&a,&b,&c); if((a>b)&&(a>c)) print f("Greatest value is a =%d",a); else if((b>a)&&(b>c)) print f("Greatest value is b=%d",b); else print f("Greatest value is c=%d",c); }
That depends on what language you're using. In PHP for example, it would be like this: $c = chr($i); In C, it would be: char c = (char)i; in BASIC, you'd use: LET C$ = CHR$(I)
its quite simple using printf function