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How to solve for the oxidation number of charge of a polyatomic ion?
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How do you solve for the oxidation number of a chlorate ion?
The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:- oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl) the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl -1 =OxCl + (3* -2)= OxCl -6 therefore OxCl = +5
How can you tell an elements oxidation number by looking at the periodic table?
1. Elements on their own have an oxidation # equal to 0. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, Ca and 2Ag would have oxidation #s equal to 0.) 2. Ions in ionic compounds have an oxidation # equal to their charge. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, 2AgCl = Ag+1 and Cl-1, and CaCl2 = Ca+2 and Cl2-1.)
What is the oxidation number of in KIO4?
+1 for K -2 for each O +7 for I
What particle has a charge of 1?
This particle is the electron.
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How do you solve for the oxidation number of a chlorate ion?
The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:- oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl) the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl -1 =OxCl + (3* -2)= OxCl -6 therefore OxCl = +5
How can you tell an elements oxidation number by looking at the periodic table?
1. Elements on their own have an oxidation # equal to 0. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, Ca and 2Ag would have oxidation #s equal to 0.) 2. Ions in ionic compounds have an oxidation # equal to their charge. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, 2AgCl = Ag+1 and Cl-1, and CaCl2 = Ca+2 and Cl2-1.)
What is the oxidation number of in KIO4?
+1 for K -2 for each O +7 for I
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31
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