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how will make solution for 0.005 h2so4
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∙ 12y ago
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H2So4 is liquidso how much ml of H2So4 take for 1N solution?
Sulphuric Acid requires, I believe 27.2ml to make a 1N solution.
How do you make 80N H2SO4 solution from 98 percent acid?
You'll never reach that because 98% H2SO4 is of lower normality: max. 37 N Density 1840 g solution / L solution Molar mass 98 g/mol H2SO4 concentration 980 gH2SO4 / 1000g solution H2SO4 2 equivalent H+/mol H2SO4 All together making: [1840*(980/1000) / 98 ] * 2 = 36.8N H2SO4 Or the other way 'round: 80N = 40M = 40*98(g/mol) = 3920 gH2SO4/L = 3920/(98*100) = 4000 g (solution)/L , which is more than the most concentrated H2SO4 solution can weight
Why you add H2SO4 in the preparation of CUSO4 solution?
It's kind of hard to make copper sulphate without any sulphate being present.
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
How to make 4.5 m H2SO4?
4.5m H2SO4 Solushen 25%
H2So4 is liquidso how much ml of H2So4 take for 1N solution?
Sulphuric Acid requires, I believe 27.2ml to make a 1N solution.
How do you make 80N H2SO4 solution from 98 percent acid?
You'll never reach that because 98% H2SO4 is of lower normality: max. 37 N Density 1840 g solution / L solution Molar mass 98 g/mol H2SO4 concentration 980 gH2SO4 / 1000g solution H2SO4 2 equivalent H+/mol H2SO4 All together making: [1840*(980/1000) / 98 ] * 2 = 36.8N H2SO4 Or the other way 'round: 80N = 40M = 40*98(g/mol) = 3920 gH2SO4/L = 3920/(98*100) = 4000 g (solution)/L , which is more than the most concentrated H2SO4 solution can weight
How do I make a 1 N sulfuric acid solution from 5.25 N sulfuric acid what is the dilution?
Mix 1 part 5,25 N H2SO4 with 4,25 parts water to obtain 1 N H2SO4.
Why you add H2SO4 in the preparation of CUSO4 solution?
It's kind of hard to make copper sulphate without any sulphate being present.
How do you prepare 2N H2SO4 and 2M H2SO4?
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
How to make 4.5 m H2SO4?
4.5m H2SO4 Solushen 25%
H2SO4 are metals?
H2SO4 is not metals. These two can go together and make H2.
How do make a 5.25N sulfuric acid solution from concentrated sulfuric acid solution?
con.H2SO4 is 98%(v/v)ie 980ml/litre.or 980X1.84(specific gravity of H2So4)ie wt/litre is 1803.2Normality= wt per litre/ Eq.wtie 1803.2/49=36.8 NHence con H2So4 is 36.8 NTo prepare 5 N , It has be diluted 7.36 times with water68
What does H2SO4 make?
Sulphuric acids
What is reaction for Cu2O plus H2SO4?
the reaction between cupperous oxide and sulphuric acid will give you a product of copper sulphate and water which is CuSO4 and H2o. I think this is correct product obtained as far as I know and this is a important chemical reation which is frequently udes in many industrial productions.
How do you make a lead acid accumulator?
we can make it by adding six lead plates in 40% h2so4 solution in suitable container by connecting the three alternate plates to a negative terminal and three plates impregnented in positive terminal
How do you make 0.02N sulfuric acid solution?
I would like to dilute some 5N sulfuric acid with water, and make 0.1N sulfuric acid solution. I want 1000ml of 0.1N . I think it's a 50 to 1 ration, but just want to make sure. <Volume of concentrated> x <Concentration of Concentrated> = <Volume of dilute> x <Concentration of dilute> Therefore, <Volume of concentrated> = <Volume of dilute> x <Concentration of dilute> / <Concentration of dilute> = 1000 mL x 0.1 N / 5N = 20 mL. Meaning: Dilute 20 mL of the 5N H2SO4 to 1000 mL in a volumetetric flask will give you 1000 mLs of 0.1 N H2SO4 (aq.).
