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How would the thinking distance be greater than the braking distance with a car?
Wiki User
∙ 16y ago
I am trying to understand your question and interpret it as meaning: How does the reaction time affect the breaking distance of a car at different speeds. The simple answer is that the reaction time "thinking distance" does not change, but the distance a car travels at higher speeds changes during that time does. For example: If you are too close to the car in front of you and they slam on their breaks, if you are both going fast enough, by the time you did your "thinking time" you would be crashing into their rear end.
Wiki User
∙ 16y ago
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If traveling 60 mph how many feet would it take you to stop?
On dry pavement in the average car it will take 60 ft of thinking about it, & 180 ft of braking for a total of 240 ft. Double the braking distance on wet pavement for a total of 420 ft. On snow it is anyone's guess.
Would the braking distance be longer or shorter if a driver drove at 100km per h?
The answer depends on compared to what? Compared to driving at 50 km per hour, the braking (not breaking!) distance would be longer, compared to 200 km per hour it would be longer.
What happen to the braking distance if the speed is doubled and why?
Hi there! Assuming that the deceleration (or negative acceleration, if you will) is constant and the same in both cases, you can use a special kinematic formula to solve the problem. The formula follows: (final velocity)^2 = (initial velocity)^2 + [ 2 * (deceleration) * (braking distance) ] Rearranged to our needs the formula reads: braking distance = [1/2] * -(initial velocity)^2 / (deceleration) * this equation assumes that the final velocity is zero If the initial speed were doubled then the general formula would read: braking distance = 2 * -(initial velocity)^2 / (deceleration) NOTICE that the two equations are the exact same except for the leading coefficients. 1/2 is assocaited with the braking distance of the normal velocity while 2 is assocated with the breaking distance of the doubled velocity. Since 2 is four times larger than 1/2, this leads us to the conclusion that the breaking distance for an object traveling at double a certain velocity would be 4x greater than the breaking distance of the object moving at the "regular" velocity.
What does your total stopping distance includes?
Total stopping distance includes both reaction distance (the distance traveled while perceiving a hazard and reacting to it) and braking distance (the distance traveled once braking has been initiated). It is the sum of these two distances and is the distance required for a vehicle to come to a complete stop.
How would braking distance be affected on rainy day?
because there is less friction between the tyre and the road because of the water in between
What would happen if a projectile were thrown with greater velocity?
A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.
What would happen if the projectile were thrown with greater velocity?
A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.
What would happen if the projectile were thrown with a greater velocity?
A projectile thrown with a greater velocity would travel a greater distance. Velocity is not just speed but direction as well.
How does friction affect the motion of a vehicle in the context of tire surface road conditions including skidding braking force braking distance thinking distance and stopping distance?
Tyre surface: If the tyre is new, it will have surface with depressions which will offer more friction compared to old tyre whose surface-depressions are worn out and it is more flat, so it offers less friction. Therefore, new tyre will have less stopping distance, as force of friction is more. Thinking distance is affected neither by friction between tyre and road, nor by friction between brake and tyre. If road has a wet surface, it has less friction so the vehicle will skid farther, and vice versa. The braking force, i.e, friction between tyre and brake is unaffected by road condition or tyre surface. Hence the distance the vehicle travels WHILE retarding due to "braking force", is not same as stopping distance, because even when the wheels are stopped rotating due to braking force, the car will skid a little distance- this total distance is the stopping distance.
Why would it be harder to open the door if you ppushed on the center?
If you push on the center there is less distance to the hinge. The greater the distance from the hinge, the greater the torque to open it for the same force ( force x distance = torque)
How would knowing that the distance that an object was dropped on a lever affect the distance that an item is launched?
Firstly, knowing this distance won't affect the launch. But the actual distance will, whether you know it or not. So, the greater this distance the more the speed of the object and so the greater the force produced on the lever.
Is distance traveled versus time at a constant speed a direct or inverse porportion?
Think about it. If you travel for more time, would you advance a greater distance (that would be a direct proportion), or less distance (that would be an inverse proportion)?
