You bridge the amp not the sub.
2 ohms of resistance
The difference between 2 ohms and 4 ohms is 2 ohms.
2 is larger that 1.8
If your sub is 2 ohms and your amp is 2 ohm stable, your done. Your amp will be at 2 ohms because the sub is 2 ohms.
135 ohms new, and will function properly down to 114 ohms. The chart in the '86-'87 book shows: Empty=110 ohms +/- 7 ohms Full=3 ohms +/- 2 ohms 1/2 full= 32.5 ohms +/- 4 ohms
Ohms is a measure of impedance (resistance), not volume.
87 to 90 YJ fuel guage sender is: 0 ohms = empty; 44 ohms = 1/2; 88 ohms = full
Purely additive. 2+3+4+5+6=20.
Purely additive. 2+3+4+5+6=20.
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
How do you get my Rockford fosgate p3001 to drop down to 2 ohms