The resulting concentration in M is 0,0118 (approx. 0,012).
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
1.0 molal
Yes. The volume you have of a particular solution does not have anything to do with the concentration of that solution.
Usually not, but you can add more solvent and remove a compensating volume of the solute. This is easest if it is a liquid-in-liquid or a gas-in-gas solution.
it is very easy to prepare working solution from a stock solution we use the formula for this purpose which is: C1V1 = C2V2 C1 is the concentration of the stock solution V1 required volume from the stock solution C2 concentration of the working solution V2 volume of the working solution
The concentration is 34,32 g/L.
.33
When a given solution is diluted, it concentration is usually lowered as well. The density of the given solution also changes when the solution is diluted.
ask your chemistry teacher at 12 PM tomorrow
The concentration of a solution is basically how strong the solution is.
The concentration of a solution is typically given in terms of the volume of solution, in liters.
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
If the concentration of alcohol and water solution is 25 percent alcohol by volume, the volume of alcohol in a 200 solution is 50.
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
Are you sure you mean 0.211 m not 0.211 M Is the concentration molality or molarity? If 55 ml of a 0.211 m NaOH is diluted to a final volume of 125 ml what is the concentration of NaOH in the diluted solution?NaOH not NaHO the compound is Sodium hydroxide Molar mass of NaOH = 23 + 16+ 1 = 40 0.211 moles of NaOH = 0.211 * 40 = 8.44 grams of NaOH per liter of solution 55 ml = 0.055 Liter 8.44 grams of NaOH per liter of solution * 0.055 liter = 0.4642 g of NaOH Moles of NaOH = 8.44 ÷ 40 = 0.211 moles 0.211 moles of NaOH in 125 ml = 0.211 moles ÷ 0.125 L = 1.688 m
It can be diluted by adding the appropriate amount of water to the solution.
You are probably looking for "dilute" but that is wrong, dilute is relative. A dilute solution of table salt (sodium chloride) can be a very different concentration to a dilute solution of slaked lime (calcium hydroxide).