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You think probable to dinitrogen pentoxide - N2O5.
Molarity is moles in every litre. Therefore you have to convert this to find out the moles in each litre. 21/52 is 0.404 molar.
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
medicines, electronic components, composite materials in aircraft and polymers
2,615 moles of aluminium oxide.
This is a mole stoichiometry problem. Start with the balanced equation for the synthesis of aluminum oxide: 4Al + 3O2 --> 2Al2O3. The ratio of aluminum to aluminum oxide in this equation is 4:2, or 2:1, so 5.23 moles Al means half that number for Al2O3, so about 2.62 moles of aluminum oxide will be produced.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (Oβ) to form aluminum oxide (AlβOβ) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (AlβOβ). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
Ther answer is none! ammonium bromide is made from hydrogen bromide and ammonia NH3 + HBr = NH4Br i mole of each makes 1mole of ammonium salt.
The potassium hydroxide is what we call the limiting reactant. 4 moles of potassium hydroxide react with 2 moles of magnesium chloride. The third mole of magnesium chloride is in excess and has no effect.
When acids react with carbonates, carbon dioxide is produced. You can test this by waiting for the chemical reaction to take place and then using a bung to insert the gas into lime water!
Given the balanced equation C10H8 + 12O2 --> 10CO2 + 4H2O In order to find the mass in grams of CO2 that can be produced from 25.0 moles of C10H8, we must convert from moles to mass (mol --> mass conversion). 25.0 mol C10H8 * 10 molecules CO2 * 44.01g CO2 = 1.1025x104 (11025)g CO2 ------------------------- 1 molecule C10H8
I2 + 2Cl2 .==> ICl + ICl3 molar mass of I2 = 127 molar mass of Cl2 = 70.9 moles of I2 used = 25.4/127 = 0.2 moles of I2 moles of Cl2 used = 14.2/70.9 = 0.2 moles of Cl2 Since the stoichiometry indicates that each mole of I2 reacts with 2 moles of Cl2 to give 1 mole each of ICl and ICl3, you should get 0.1 moles of each product. The reason you don't get 0.2 moles is because the amount of I2 is limiting, and you can see that 2 moles of Cl2 will use up 1 mole of I2, so 0.2 moles of Cl2 will use up 0.1 moles of I2. So 0.1 moles of product is all you can get under these conditions
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
the name given to chemicals which react together is products
If there is ample O2 then no CO will be produced, all the C will be made into CO2. You therefore need to make your question more precise regarding the proportions of the reactants present at the start if you want us to answer you.