If 3 moles of a compound use 24 J of energy in a reaction, the H reaction is 8 J/mol.
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
24 J/3 moles = 8 J/mole
0.004 kJ/mol
0.004 is correct -apex
.0004
Approx 3.29 moles.
The coefficient (in this case a 2) indicates the number of moles or molecules of the compound. So, 2NH3 means there are 2 moles or 2 molecules of ammonia (NH3).
There are 15 moles of ammonia sulfate in the reaction of 30.0 mol of NH3. This goes from the formula 2 NH3 H2so take away (NH4)2So4.
1
Lead(II) sulphate has the molecular formula of PbSO4. The molecular weight of PbSO4 is 303.3 grams per mole. A sample weight of 158.1 grams corresponds to .5213 moles of PbSO4.
-14 J/Mol
84 J/6 moles = 14 J/mole = ∆H
84 J/6 moles = 14 J/mole = ∆H
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
-14 J/mol
-14 J/mol
This isn't a legitimate question.... How many moles of what? You would need to give the reaction to know then, mole to mol ratio and the amount of mols in each compound and to figure out the molar mass of each.
Approx 3.29 moles.
6 moles
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
The formula means, among other things, that there are 7 atoms of oxygen in each mole of the compound. Therefore, in 4.00 moles of the compound, there are 28.00 moles of oxygen atoms. Elemental oxygen usually is diatomic, so that there would be the equivalent of 14 moles of diatomic elemental oxygen.