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Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
-14 J/mol
This isn't a legitimate question.... How many moles of what? You would need to give the reaction to know then, mole to mol ratio and the amount of mols in each compound and to figure out the molar mass of each.
6 moles
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
-14 J/Mol
84 J/6 moles = 14 J/mole = ∆H
84 J/6 moles = 14 J/mole = ∆H
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
-14 J/mol
-14 J/mol
This isn't a legitimate question.... How many moles of what? You would need to give the reaction to know then, mole to mol ratio and the amount of mols in each compound and to figure out the molar mass of each.
It means you have three moles on your thigh.
Approx 3.29 moles.
6 moles