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-14 J/mol
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
This isn't a legitimate question.... How many moles of what? You would need to give the reaction to know then, mole to mol ratio and the amount of mols in each compound and to figure out the molar mass of each.
6 moles
-14 J/mol
-14 J/mol
12 J/3 moles = 4 J/mole. Thus, H of reaction in kJ/mole = 0.004 kJ/mole
-14 J/Mol
84 J/6 moles = 14 J/mole = ∆H
84 J/6 moles = 14 J/mole = ∆H
Carbon dioxide is the limiting reagent.
This is the number before a chemical compound.
This isn't a legitimate question.... How many moles of what? You would need to give the reaction to know then, mole to mol ratio and the amount of mols in each compound and to figure out the molar mass of each.
Approx 3.29 moles.
6 moles
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?