The brown eyed woman is heterozygous genotype with a dominance of brown eyes, usually represented Bb -- capital 'B' as the brown gene and lower case 'b' as the blue gene. She has the possibility of passing both blue and brown eyes onto her offspring, however blue eyes only have a 25% chance of being expressed in the offspring The brown eyed woman is heterozygous genotype with a dominance of brown eyes, usually represented Bb -- capital 'B' as the brown gene and lower case 'b' as the blue gene. She has the possibility of passing both blue and brown eyes onto her offspring, however blue eyes only have a 25% chance of being expressed in the offspring
Brown eye gene = B
Blue eye gene = b
Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb.
If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes.
If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
In this case both parents must be heterozygous to have this child. This means the mother will have the genotype AO and the father will have the genotype BO. In order to have blood type O, the child must have the genotype OO.
Her father has to have hemophilia as well, and the mother is a carrier or also has hemophilia. So if we pretend that the hemophilia gene is "x", you need to have "xx" to have hemophilia. The father must have the genotype "Yx" and the mother has the have "Xx" or "xx".
Her blood type will be A.
Xi or just X depending on how you want to write it
willies that are 2 inches are medically health hazards
The mother's genotype is rr. The daughter would inherit one recessive allele from her mother because her mother has only recessive alleles. Because the daughter is green eyed, she would inherit a dominant allele from her father. The brown-eyed daughter's genotype would be Rr.
In this case both parents must be heterozygous to have this child. This means the mother will have the genotype AO and the father will have the genotype BO. In order to have blood type O, the child must have the genotype OO.
Yes.
The plural of "woman" is "women". "Womans" is not a plural form of the word "woman".
The genotype of the man is A negative/O negative inheriting the A neg from his mother and O negative from his father. [Father's genotype is B positive/O negative. Mother's genotype is B positive/A negative.]
A woman with type A blood may have genotype AO or AA. The heterozygous type is AO.
The man's genotype is CcFf. The woman's genotype is CcFf. These genotypes only apply if curly hair is dominant to straight hair. Freckles is dominant to no freckles. Also if a man who is heterozygous for both curly hair and freckles who then marries a woman with the same genotype.
A womans name.
She is a carrier of hemophilia but does not have the condition
Yes, if the mother's genotype is BO, she may pass the O allele on to the child and it will be type O.
It ends with i, WOMANS NAME
the constellation and womans name is norma