I believe its like this but don't take my word for granted: R (resistance) = V (voltage) / I (amperes) The formula is R = V/I R = 110V / 10A R = ? R = 110/10 = 11 R = 11Ω Ω= omhs Hope this helped but as I said I'm not completely sure
Assume the supply as DC (Only resistance given) Voltage drop = 10X10X0.12 = 12V (approx)
By far a toaster draws more current than a light bulb.
To find the resistance necessary, one would need to know how much current the bulb draws. If one knows the current the bulb draws, then one would subtract the 14 volts from 120 volts then divide that by the current the bulb draws and one will find the resistance needed. Once this has been done, one would need to multiply the current drawn by the voltage drop to get the wattage rating necessary. Another important detail to note is that the power dissipated by the resistor will be much greater than the power consumed by the bulb itself. Finally if the bulb burns out the voltage across the contacts will be 120V. I would not recommend using this method to drop the voltage for the bulb.
The voltmeter has an internal resistance, which should be as high as possible. As this resistance draws current from the circuit under test, it will affect circuit operation. This is more pronounced in a high impedance circuit because the current drawn flows through higher resistances.
375 kj
Assume the supply as DC (Only resistance given) Voltage drop = 10X10X0.12 = 12V (approx)
We know that Voltage = Current x Resistance, so if E = I x R, then E = 20 x 12 = 240 volts, and the dryer must be plugged into a 240 volt outlet.
Ohm's Law says Voltage = Current x Resistance V = 5 x 24 = 120 V.
The voltage is the main power of a toaster!! but if the current flow is low the heat of the toaster is less heat that you expect, the 8 A is right for your toaster!!!
Your hair dryer has a resistance of 220/12 = Ohms. (I'm sure you can do the math.)
By far a toaster draws more current than a light bulb.
yes they do check lowes A 20 amp breaker is normally used in a kitchen or any where a item such as a A/C unit is going to be installed, something that draws alot of power or has heat involved with it (toaster oven ect.)
Power (Watts) = Current (Amps) * VoltagePower = 22Amps * 240 VoltsPower = 5,280 Watts5280
yes they do, in fact the toaster draws power more when it is not in use
how much energy it draws from your outlet or car battery.
The voltage of a battery goes as the current times the resistance (V=IR). Because the voltage is being held constant, the resistor that draws the most current will have the lower resistance.
I have no idea