The offspring will get the qualities , traits of homozygous BB.
The offspring will get the traits of Homozygous BB .
If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.
To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
To calculate the probability of a homozygous dominant (BB) offspring from a cross between two rabbits, we need to consider their genotypes. If both parents are heterozygous (Bb), the possible offspring genotypes would be BB, Bb, Bb, and bb, giving a probability of 1 out of 4, or 25%, for a homozygous dominant (BB) offspring. If one parent is homozygous dominant (BB) and the other is heterozygous (Bb), the probability of BB offspring is 1 out of 2, or 50%.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
When black dominates white in certain rat species, the genotype of the black rat would be homozygous dominant (BB), while the genotype of the white rat would be homozygous recessive (bb). When two hybrid black rats (Bb) are crossed, the possible genotypes of their offspring would be 25% homozygous dominant (BB), 50% hybrid (Bb), and 25% homozygous recessive (bb).
To solve a Punnett square for two parents with genotype Bb (heterozygous for the same gene), you would set up a 2x2 grid. The possible combinations in the offspring would be BB, Bb, Bb, and bb. This results in a 25% chance of the offspring being BB (homozygous dominant), a 50% chance of being Bb (heterozygous), and a 25% chance of being bb (homozygous recessive).
To determine the hair color of the guinea pigs' offspring, we need to know the genotypes of the parents. If one parent is homozygous dominant (BB) and the other is homozygous recessive (bb), all offspring will be heterozygous (Bb) and will have black hair. If both parents are heterozygous (Bb), approximately 25% of the offspring are expected to be homozygous dominant (BB), 50% heterozygous (Bb), and 25% homozygous recessive (bb), resulting in a 75% chance of black hair and a 25% chance of white hair.
Both parents were heterozygous (Bb). The offspring would statistically be: BB, Bb, Bb, and bb. All but the bb offspring would be black and the bb would be brown.
If both parents are black-haired guinea pigs and the black coat color is dominant, they could either be homozygous (BB) or heterozygous (Bb) for the black coat gene. If both are heterozygous (Bb), the offspring ratio would typically be 25% homozygous black (BB), 50% heterozygous black (Bb), and 25% brown (bb). Therefore, among the 20 offspring, we would expect around 15 to be black (BB or Bb) and about 5 to be brown (bb) if the parents are Bb. If both parents are homozygous (BB), all offspring would be black.
The black guinea pig is likely heterozygous (Bb) for coat color, while the white guinea pig is homozygous recessive (bb). The black guinea pig passes on a black allele to all offspring, resulting in 4 black (Bb) and 2 white (bb) offspring.